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anonymous

  • 5 years ago

integral of 625x^3(e^5x), use integration by parts

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  1. anonymous
    • 5 years ago
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    i know how to start it off, i just keep getting the wrong anser tho

  2. anonymous
    • 5 years ago
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    long integration involves, select 625x^3 as a first function

  3. anonymous
    • 5 years ago
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    what did u get?

  4. anonymous
    • 5 years ago
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    i got \[e^5x(125x^3-75x^2-30x-6)+C\]

  5. anonymous
    • 5 years ago
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    e^(5x)*

  6. anonymous
    • 5 years ago
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    when u select 625x^3 as a first function, u write the derivative of it,right?

  7. anonymous
    • 5 years ago
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    power must be reduced

  8. anonymous
    • 5 years ago
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    i followed an example in the book, and it used x^3 as the u value, and 625e^5x as va

  9. anonymous
    • 5 years ago
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    v

  10. anonymous
    • 5 years ago
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    u mean the reduction formula

  11. anonymous
    • 5 years ago
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    use 5x = t t^3 (e^t)dt

  12. anonymous
    • 5 years ago
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    then use integral by parts

  13. anonymous
    • 5 years ago
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    what reduction formula did u use?

  14. anonymous
    • 5 years ago
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    him is right

  15. anonymous
    • 5 years ago
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    m e?

  16. anonymous
    • 5 years ago
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    ok i got the write answer now,lol sorry nvrmind, but thanks guys :)

  17. anonymous
    • 5 years ago
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    things got easy now

  18. anonymous
    • 5 years ago
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    no him it wasnt you :)

  19. anonymous
    • 5 years ago
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    ok amk....

  20. anonymous
    • 5 years ago
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    glad 2 help...

  21. anonymous
    • 5 years ago
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    so him...u feeling fresh now? :)

  22. anonymous
    • 5 years ago
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    thnx fr asking...yeah better now..nthn a coke wont heal

  23. anonymous
    • 5 years ago
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    medal for ur determination :)

  24. anonymous
    • 5 years ago
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    u must feel much better now:P

  25. anonymous
    • 5 years ago
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    yeah thnx

  26. anonymous
    • 5 years ago
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    :)

  27. myininaya
    • 5 years ago
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    well i just did all of this work without reading any of that above stuff so here you go lol

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  28. anonymous
    • 5 years ago
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    myin: the anser was actually (125x^3-75x^2+30x-6)e^5x +C, u were right with the first two numbers, but thanku so much for taking the time to work it out :)

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