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anonymous
 5 years ago
How to get from this equation x^3 + 4x^210=0 to this equation x = x  [(x^3 + 4x^210)/ (3x^2+8x)]
anonymous
 5 years ago
How to get from this equation x^3 + 4x^210=0 to this equation x = x  [(x^3 + 4x^210)/ (3x^2+8x)]

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so the original equation we divide it by (3x^2+8x) assuming that this in not zero because you cannot divide by zero so we have (x^3+4x^210)/[(3x^2+8x]=0 (x^3+4x^210)/(3x^2+8x)=0 now add x no both sides x(x^3+4x^210)/(3x^2+8x)=x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0are there any questions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not really, thanks thou for help. I am still thinking about our solution

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0you wanted to know how to write that one equation as that other equation right? you didn't want to use newton's method to find the xintercepts? did you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) = x^3 + 4x^2 10 = 0 x^3 + 4x^2 10 = 0 x^3 + 4x^2 = 10 x^2 = 10/(4+x) x = g4(x) = (10/(4+x))^(1/2) f(x) = x^3 + 4x^2 10 = 0 x^3 + 4x^2 10 = 0 4x^2 = x^3 + 10 x^2 = (x^3 + 10)/4 x = ((x^3 + 10)/4)^0.5 x = g3(x) = ((x^3 + 10)/4)^0.5 f(x) = x^3 + 4x^2 10 = 0 x^3 + 4x^2 10 = 0 x^3 = 10  4x^2 x^2 = (10  4x^2)/x x = g2(x) = ((10  4x^2)/x)^(1/2) see all these equations I didn't need to add or divide any extra equations. However, your answer looks good, but you did add extra stuff there to reach the second equation. I am wondering if there will be anyway to reach the second equation without adding extra things in the original equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am trying here to solve the original equation for x. There are five ways to solve the equation for x, I only got four ways.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0so you do know newton's method?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0that second equation is looks like newton's method x1=x0f(x0)/f'(x0) f'(x0) not equal to zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know about the newton's method. I need to solve the original equation for x in five different ways, then I need to verify that each of the five equations converges with the same fixed point of original equation. I know three of them will converge, except one. I got to figure out how to find the fifth equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know about the newton's method. I need to solve the original equation for x in five different ways, then I need to verify that each of the five equations converges with the same fixed point of original equation. I know three of them will converge, except one. I got to figure out how to find the fifth equation
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