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anonymous
 5 years ago
Is there another way to find the flux of the gradient of a scalar field through a shape than just taking the line integral for a vector field?
anonymous
 5 years ago
Is there another way to find the flux of the gradient of a scalar field through a shape than just taking the line integral for a vector field?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats was going to be my next chapter that i read to the kids for a bedtime story :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The function i have gives me an unsolvable integral when i use a line integral to find the flux of the gradient..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what does flux of a gradient mean; i know what a gradient is; but flux?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sounds like soldering :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im given a scaler field im told to find the gradient and integrate it around a shape

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the gradient that is.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im gonna read vector fields tonight; i hope its steamy ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0xe^(yz) my shape is r(t)=<2rcos(t),rcos(t),2sqrt(2)sin(t)> t is between 0 and pi and my r is 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Ok; the gradient should be the derivatives of your function in vector format..right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gF(x,y,z) = <dF/dx, dF/dy, dF/dz> right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i cant take the strait line integral and stokes doesnt work because the curl of the grad is zero

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0gF = <e^(yz),zx.e^(yz),yx.e^(yz)> the gradient vector right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats the extent of my abilities with that :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0prolly not :)....give me a week ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maybe a little longer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No he's taking the same class you are (calc 3) so he'll probably be covering this later in the term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0found it http://en.wikipedia.org/wiki/Line_integral#Path_independence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0didnt cover this in calc 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0really? It was covered in my 3rd semester calc class along with surface integrals, etc. Stoke's, Green's, etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0flux but not this indepth of line integral theory
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