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thats was going to be my next chapter that i read to the kids for a bedtime story :)
The function i have gives me an unsolvable integral when i use a line integral to find the flux of the gradient..
what does flux of a gradient mean; i know what a gradient is; but flux?
sounds like soldering :)
im given a scaler field im told to find the gradient and integrate it around a shape
the gradient that is.
whats the function?
im gonna read vector fields tonight; i hope its steamy ;)
xe^(yz) my shape is r(t)=<-2rcos(t),rcos(t),2sqrt(2)sin(t)> t is between 0 and pi and my r is 2
Ok; the gradient should be the derivatives of your function in vector format..right?
i cant take the strait line integral and stokes doesnt work because the curl of the grad is zero
the gradient vector right?
thats the extent of my abilities with that :)
what is a flux?
you cant help me
prolly not :)....give me a week ;)
maybe a little longer
No he's taking the same class you are (calc 3) so he'll probably be covering this later in the term
found it http://en.wikipedia.org/wiki/Line_integral#Path_independence
im taking vectors
didnt cover this in calc 3
really? It was covered in my 3rd semester calc class along with surface integrals, etc. Stoke's, Green's, etc
flux but not this indepth of line integral theory