## anonymous 5 years ago Is there another way to find the flux of the gradient of a scalar field through a shape than just taking the line integral for a vector field?

1. amistre64

thats was going to be my next chapter that i read to the kids for a bedtime story :)

2. anonymous

The function i have gives me an unsolvable integral when i use a line integral to find the flux of the gradient..

3. amistre64

what does flux of a gradient mean; i know what a gradient is; but flux?

4. amistre64

sounds like soldering :)

5. anonymous

im given a scaler field im told to find the gradient and integrate it around a shape

6. anonymous

7. amistre64

whats the function?

8. amistre64

im gonna read vector fields tonight; i hope its steamy ;)

9. anonymous

xe^(yz) my shape is r(t)=<-2rcos(t),rcos(t),2sqrt(2)sin(t)> t is between 0 and pi and my r is 2

10. amistre64

Ok; the gradient should be the derivatives of your function in vector format..right?

11. amistre64

gF(x,y,z) = <dF/dx, dF/dy, dF/dz> right?

12. anonymous

yeah

13. anonymous

i cant take the strait line integral and stokes doesnt work because the curl of the grad is zero

14. amistre64

gF = <e^(yz),zx.e^(yz),yx.e^(yz)> the gradient vector right?

15. anonymous

yup

16. amistre64

thats the extent of my abilities with that :)

17. anonymous

...

18. amistre64

what is a flux?

19. anonymous

you cant help me

20. amistre64

prolly not :)....give me a week ;)

21. anonymous

maybe a little longer

22. anonymous

No he's taking the same class you are (calc 3) so he'll probably be covering this later in the term

23. anonymous
24. anonymous

im taking vectors

25. anonymous

didnt cover this in calc 3

26. anonymous

really? It was covered in my 3rd semester calc class along with surface integrals, etc. Stoke's, Green's, etc

27. anonymous

flux but not this indepth of line integral theory