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anonymous

  • 5 years ago

Need a little help--Instantaneous velocity: (derivatives) s=8t(squared)-10t+6; t=5. any help?,Thanks

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  1. anonymous
    • 5 years ago
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    Just use the sum rule. The derivative of a sum is the sum of the derivatives of each term.

  2. myininaya
    • 5 years ago
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    s'=2*8t-10 s'(5)=16(5)-10

  3. anonymous
    • 5 years ago
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    so s=156?

  4. anonymous
    • 5 years ago
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    No, s'(5) = 156

  5. myininaya
    • 5 years ago
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    s'(5)=80-10=70 did i miss something?

  6. anonymous
    • 5 years ago
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    yeah, it's 70

  7. anonymous
    • 5 years ago
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    I didn't check his arithmetic. In anycase, this is the trouble with just solving people's problems myininaya. They don't understand what you did, so they don't understand the answer, or how to do it again next time.

  8. anonymous
    • 5 years ago
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    can you take it step by step for me ? now I am missing something , Thanks

  9. myininaya
    • 5 years ago
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    do you know how to find the derivative?

  10. anonymous
    • 5 years ago
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    yes

  11. myininaya
    • 5 years ago
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    what is s' = then?

  12. anonymous
    • 5 years ago
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    Prime

  13. myininaya
    • 5 years ago
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    what is s'=______________?

  14. anonymous
    • 5 years ago
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    oh - i got 156

  15. myininaya
    • 5 years ago
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    the derivative of 8t^2 is? the derivative of 10t is? the derivative of constant is?

  16. myininaya
    • 5 years ago
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    no clown i'm asking what is s' not what s' at some number is

  17. anonymous
    • 5 years ago
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    16t,10,0

  18. myininaya
    • 5 years ago
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    so s'=16t+10+0=16t+10

  19. myininaya
    • 5 years ago
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    oops s'=16t-10 i forgot the minus in the problem

  20. myininaya
    • 5 years ago
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    so what is s' at t=5

  21. anonymous
    • 5 years ago
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    Man your rough! but you make me think! ---- Thanks

  22. myininaya
    • 5 years ago
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    i'm rough lol

  23. myininaya
    • 5 years ago
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    do you get 70 now?

  24. anonymous
    • 5 years ago
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    Hold on Im old!

  25. anonymous
    • 5 years ago
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    yes, Thank you , Wow ! LOL

  26. myininaya
    • 5 years ago
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    you really got it? ok what's the instanteous velocity of s=t^4-6^2+3 at t=3

  27. anonymous
    • 5 years ago
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    Oh and by the way I am a real clown, A Shriner Clown

  28. myininaya
    • 5 years ago
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    s=t^4-6t^2+3

  29. myininaya
    • 5 years ago
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    cool. lol

  30. anonymous
    • 5 years ago
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    s=45?

  31. myininaya
    • 5 years ago
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    what is s' ?

  32. anonymous
    • 5 years ago
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    um, ok im lost ! Help!!

  33. myininaya
    • 5 years ago
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    we want to find the instanteous velocity of s=t^4-6t^2+3 at t=3 finding velocity means we need to find the derivative of s s' denotes the derivative first let's break this up what is the derivative of t^4? what is the derivative of -6t^2? what is the derivative of 3?

  34. anonymous
    • 5 years ago
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    3t,12t,0

  35. anonymous
    • 5 years ago
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    -12t oops

  36. myininaya
    • 5 years ago
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    derivative of t^4 is 4*t^3 i used the power rule everything else you got right so 2/3 is passing

  37. anonymous
    • 5 years ago
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    you funny and yes you are right about the first answer , you are making me think faster than normal! and making me nervous! I do not want to come off to you as a complete rock!

  38. myininaya
    • 5 years ago
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    i'm sorry

  39. myininaya
    • 5 years ago
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    lol take as much time as you need

  40. anonymous
    • 5 years ago
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    ok, Thanks! Just wish sometimes I was better at this stuff, like you- I love smart math people!

  41. myininaya
    • 5 years ago
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    clowns are cool too

  42. myininaya
    • 5 years ago
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    let's put all the terms of s' together so s'=?

  43. anonymous
    • 5 years ago
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    ok, hold, please

  44. myininaya
    • 5 years ago
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    k

  45. anonymous
    • 5 years ago
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    s=96

  46. myininaya
    • 5 years ago
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    i don't think thats right and like polak said before its s'(3)=96 tell me what s' is first

  47. myininaya
    • 5 years ago
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    s'(t)=

  48. anonymous
    • 5 years ago
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    4(3)^3-12+3 Right?

  49. myininaya
    • 5 years ago
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    s'(3)=4(3)^3-12(3)

  50. myininaya
    • 5 years ago
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    remember we said the derivative of t^4 is 4t^3 the derivative of -6t^2 is -12t the derivative of 3 is 0

  51. anonymous
    • 5 years ago
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    OK!!!!! 3 is prime right?

  52. myininaya
    • 5 years ago
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    yes 3 is prime since 3 is a constant, its slope is zero, and since its slope is zero then the derivative of 3 is zero

  53. anonymous
    • 5 years ago
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    we had a- 6t in the original problem? sorry my Bad yes we did, SO SORRY!

  54. anonymous
    • 5 years ago
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    Hold on

  55. anonymous
    • 5 years ago
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    s= 144+ 3?

  56. anonymous
    • 5 years ago
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    or just 144?

  57. amistre64
    • 5 years ago
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    ok...so whats our question?

  58. myininaya
    • 5 years ago
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    s=t^4-6t^2+3 find velocity at t=3 i think hes getting mixed up on where things go

  59. amistre64
    • 5 years ago
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    so clown; you say you can find a derivative; right?

  60. anonymous
    • 5 years ago
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    I thought so, guess not

  61. amistre64
    • 5 years ago
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    go ahead and give it a shot, i wanna see what you are doing

  62. amistre64
    • 5 years ago
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    what is the derivative of: t^4 -6^t +3 ??

  63. anonymous
    • 5 years ago
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    Here is my problem..... s=8t^2 -10t +6; t=5

  64. amistre64
    • 5 years ago
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    ok....lets work with 8t^2 -10t +6; what do you think the derivative should look like?

  65. anonymous
    • 5 years ago
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    16t- 10 + 6

  66. amistre64
    • 5 years ago
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    very close; the first and second terms are good; that last terms should be a 0 tho. do you know why?

  67. anonymous
    • 5 years ago
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    because there is no constant?

  68. amistre64
    • 5 years ago
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    does 6 = 6 t^0 ? and if so; how would you derive: 6 t^0?

  69. anonymous
    • 5 years ago
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    Yes , due to the fact of the power 0

  70. amistre64
    • 5 years ago
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    good; then lets rewrite this in terms you can see :) 8t^2 -10t +6t^0; now derive that for me...

  71. anonymous
    • 5 years ago
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    16t-10+6

  72. amistre64
    • 5 years ago
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    16t is good; -10 is excellent. but 6 is wrong, you didnt derive it the same way you did the others ...why not? derive 6t^0. in exactly the same way as you did the others. what do we get?

  73. anonymous
    • 5 years ago
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    0

  74. amistre64
    • 5 years ago
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    that is correct:) so would you agree that our derivative is then: 16t-10 ?

  75. anonymous
    • 5 years ago
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    Yes

  76. amistre64
    • 5 years ago
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    ds -- = 16t-10 very good; now when t=5, what does this equal? dt

  77. anonymous
    • 5 years ago
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    70!! I got it and you did not leave me at the train depot!!! YEA!!!!!

  78. amistre64
    • 5 years ago
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    yay!!! :)

  79. anonymous
    • 5 years ago
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    Thaank you very much!!!

  80. amistre64
    • 5 years ago
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    youre welcome :)

  81. anonymous
    • 5 years ago
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    Talk to ya soon maybe

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