## anonymous 5 years ago $\sqrt{x+\Delta x} \approx ?$

1. anonymous

$\sqrt{x1}$

2. anonymous

because $\sqrt{x + (x1-x)} = \sqrt{ x1}$

3. anonymous

is that $\sqrt{\Delta x}$

4. anonymous

?

5. anonymous

or $\sqrt{\Delta y}$

6. anonymous

no ... $\Delta x = x1 - x$

7. anonymous

?

8. anonymous

but there is no such option?

9. anonymous

X1 represents any variable that is not x .. you can name it whatever

10. anonymous

so inside the square root x-Δx = x - (x1 - x).. the xs cancel out so you get x1

11. anonymous

ohkay i got it.