anonymous
  • anonymous
\[\sqrt{x+\Delta x} \approx ?\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[\sqrt{x1}\]
anonymous
  • anonymous
because \[\sqrt{x + (x1-x)} = \sqrt{ x1} \]
anonymous
  • anonymous
is that \[\sqrt{\Delta x}\]

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anonymous
  • anonymous
?
anonymous
  • anonymous
or \[\sqrt{\Delta y}\]
anonymous
  • anonymous
no ... \[\Delta x = x1 - x\]
anonymous
  • anonymous
?
anonymous
  • anonymous
but there is no such option?
anonymous
  • anonymous
X1 represents any variable that is not x .. you can name it whatever
anonymous
  • anonymous
so inside the square root x-Δx = x - (x1 - x).. the xs cancel out so you get x1
anonymous
  • anonymous
ohkay i got it.

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