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hatemath

  • 5 years ago

hi my name is pj and i need help with this problem? solve the quadratic equation x2+6x+8=0

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  1. polpak
    • 5 years ago
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    You can either factor it, or use the quadratic equation

  2. polpak
    • 5 years ago
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    Which do you want to do?

  3. aama100
    • 5 years ago
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    x = 1/6 (-8 - x2)

  4. aama100
    • 5 years ago
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    {{x = -4}, {x = -2}} ignore my fist post

  5. hatemath
    • 5 years ago
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    how do i factor it?

  6. polpak
    • 5 years ago
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    You look for two numbers that add together to give you 6 (the coefficient of the middle term), and multiply to give you 8 (the last term).

  7. hatemath
    • 5 years ago
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    ok

  8. polpak
    • 5 years ago
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    So what two numbers add to make 6 and multiply to be 8 ?

  9. hatemath
    • 5 years ago
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    2 and 4

  10. polpak
    • 5 years ago
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    Correct. So we can factor \(x^2+6x+8\) into \((x+4)(x+2)\). And if our original expression was equal to 0 then the factored form will also equal 0. \((x+4)(x+2) = 0 \implies x= -4 \text{ or } x = -2\)

  11. hatemath
    • 5 years ago
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    thank you

  12. hatemath
    • 5 years ago
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    (x+6)(x-8)=0 is that x2+6x-8=0?

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