anonymous
  • anonymous
hi my name is pj and i need help with this problem? solve the quadratic equation x2+6x+8=0
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
You can either factor it, or use the quadratic equation
anonymous
  • anonymous
Which do you want to do?
anonymous
  • anonymous
x = 1/6 (-8 - x2)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
{{x = -4}, {x = -2}} ignore my fist post
anonymous
  • anonymous
how do i factor it?
anonymous
  • anonymous
You look for two numbers that add together to give you 6 (the coefficient of the middle term), and multiply to give you 8 (the last term).
anonymous
  • anonymous
ok
anonymous
  • anonymous
So what two numbers add to make 6 and multiply to be 8 ?
anonymous
  • anonymous
2 and 4
anonymous
  • anonymous
Correct. So we can factor \(x^2+6x+8\) into \((x+4)(x+2)\). And if our original expression was equal to 0 then the factored form will also equal 0. \((x+4)(x+2) = 0 \implies x= -4 \text{ or } x = -2\)
anonymous
  • anonymous
thank you
anonymous
  • anonymous
(x+6)(x-8)=0 is that x2+6x-8=0?

Looking for something else?

Not the answer you are looking for? Search for more explanations.