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anonymous
 5 years ago
Solve for x algebraically in 7^(x+2) = 0.005, rounding your answers to three signicant digits.
A) 4.32
B) 4.72
C) 5.12
D) 5.52
E) 5.92
anonymous
 5 years ago
Solve for x algebraically in 7^(x+2) = 0.005, rounding your answers to three signicant digits. A) 4.32 B) 4.72 C) 5.12 D) 5.52 E) 5.92

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take log to base 7 on both sides 2x = log 0.005 to base 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use the base change formula then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know why you've posted 3 times this same equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02x = [log0.005/log 7]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Particularly, since people were helping you in the previous two versions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0aama100: that's some impressive calculator work. If only your tutoring skills were that good people might actually learn something.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you him1618, I understand what I was supposed to do now. Its easier for me to figure out math when I see the equation in front of me because I am a visual learner.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can just use the base 10 log and you end up with the same thing \[log(7^{x2}) = log(5/1000)\] \[\implies (x2)log(7) = log(5)  log(1000)\] \[\implies x2 = \frac{log(5)  3}{log(7)} \implies x = \frac{log(5)  3}{log(7)} + 2\]
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