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remidia
Group Title
Solve for x algebraically in 7^(x+2) = 0.005, rounding your answers to three signicant digits.
A) 4.32
B) 4.72
C) 5.12
D) 5.52
E) 5.92
 3 years ago
 3 years ago
remidia Group Title
Solve for x algebraically in 7^(x+2) = 0.005, rounding your answers to three signicant digits. A) 4.32 B) 4.72 C) 5.12 D) 5.52 E) 5.92
 3 years ago
 3 years ago

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him1618 Group TitleBest ResponseYou've already chosen the best response.0
take log to base 7 on both sides 2x = log 0.005 to base 7
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
use the base change formula then
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
I don't know why you've posted 3 times this same equation
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
2x = [log0.005/log 7]
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
Particularly, since people were helping you in the previous two versions
 3 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
to the base 10
 3 years ago

aama100 Group TitleBest ResponseYou've already chosen the best response.0
x > 4.7228
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
aama100: that's some impressive calculator work. If only your tutoring skills were that good people might actually learn something.
 3 years ago

remidia Group TitleBest ResponseYou've already chosen the best response.0
Thank you him1618, I understand what I was supposed to do now. Its easier for me to figure out math when I see the equation in front of me because I am a visual learner.
 3 years ago

aama100 Group TitleBest ResponseYou've already chosen the best response.0
thanks polpak
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
You can just use the base 10 log and you end up with the same thing \[log(7^{x2}) = log(5/1000)\] \[\implies (x2)log(7) = log(5)  log(1000)\] \[\implies x2 = \frac{log(5)  3}{log(7)} \implies x = \frac{log(5)  3}{log(7)} + 2\]
 3 years ago
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