A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
3/3sqrt2sqrt3 rationalize the denominator and simplify can i get an explanation please
anonymous
 5 years ago
3/3sqrt2sqrt3 rationalize the denominator and simplify can i get an explanation please

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is your original expression: a) \(\frac{3}{3\sqrt{2}  \sqrt{3}}\) b) \(\frac{3}{3\sqrt{2}}  \sqrt{3}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so multiply top and bottom by the conjugate \(3\sqrt{2} + \sqrt{3}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, anything you do to the denominator you must do to the numerator to keep the ratio the same.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Anything you multiply the denominator by that is. \[\frac{4}{3} = \frac{4*2}{3*2} = \frac{8}{6}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im still confused i wrote this \[3/3\sqrt2\sqrt3 *3\sqrt2+\sqrt3/3\sqrt2+\sqrt3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3/3\sqrt2\sqrt3 * 3\sqrt2+\sqrt3/3\sqrt2+\sqrt3\]i mean

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to use parentheses

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3}{3\sqrt{2}  \sqrt{3}} = \frac{3(3\sqrt{2} + \sqrt{3})}{(3\sqrt{2}  \sqrt{3})(3\sqrt{2} + \sqrt{3})}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And on bottom we get some nice simplification.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand how that simplifies

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Foil it out.. \[(3\sqrt{2}  \sqrt{3})(3\sqrt{2} + \sqrt{3})\] \[=3\sqrt{2}*3\sqrt{2}  3\sqrt{2}\sqrt{3} +3\sqrt{2}\sqrt{3} \sqrt{3}*\sqrt{3}\] \[=9(2) + 0  3 = 15\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which cancels with the 3 up top

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to give you \[\frac{3\sqrt{2} + \sqrt{3}}{5}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am not grasping this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand how you got 15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand how you got 15

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is what you had in the denominator right? \[(3\sqrt{2}  \sqrt{3})(3\sqrt{2} + \sqrt{3})\] This is just like \[(a  b)(a+b) = a^2 ba + ab  b^2\] The middle two terms cancel each other out and you are left with \[a^2  b^2\] Where in your case, \(a=3\sqrt{2}\) and \(b=\sqrt{3}\) So: \[a^2  b^2 \]\[= (3\sqrt{2})^2  (\sqrt{3})^2 \]\[= 3^2\sqrt{2}^2  \sqrt{3}^2 \]\[=9(2)  3 = 183 = 15\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understand the foil method better thankyou i understand now
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.