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but how to do it?

that's a bit long process

[(b-a)/n] [f(a)+f(b)+1/2(f(all the rest))] right?

do you know how to fid the tangent line approximation of f(x)=sin2x+cosx at (pi/2. 0)

it looks doable

you mean the equation of the tangent line at (pi/2,0) right?

i know how to find the equation but
approximating making some boxes i dont know

derive the function and solve it for the input values to get the 'slope' of yout line equation

f'(x) = 2cos(2x)-sin(x) right?

or am i thinking of something else lol

ok yes thats right