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anonymous
 5 years ago
analyze and sketch the graph of f(x)=(x^2+1)/(x^24). Write the domain, asymptotes, local extrema and inflection point if any.
anonymous
 5 years ago
analyze and sketch the graph of f(x)=(x^2+1)/(x^24). Write the domain, asymptotes, local extrema and inflection point if any.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We can factor out the denominator as follows (x+2)(x2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02,2 are your verticle retricemtote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how to find the domain and point of inflection

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0domain is everywhere except 2,2 For inflection point and extrema you will need to take derivative of the function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to take derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes then after taking derivative what shall i do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The first derivative function F'[x], find out where it is zero; this is where extrema are located. For inflection point take derivative again F''[x], and find out where the function is zero; This is your inflction point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0derivative is ((x^24)(2x)(x^2+1)(2x))/(x^24)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i equated it to zero..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then what shall I do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then the extrema is at x=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can find the inflection point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it says to find local extrema is that the local extrema value.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To find local extrema, create a number line from negative infinity to positive, investigate at critical points, the point where first derivative goes from pos to neg or vice versa: local extrema.
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