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- anonymous

how do i solve y''+y = (Dirac(t-2*pi))*cos(t) ??

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- anonymous

how do i solve y''+y = (Dirac(t-2*pi))*cos(t) ??

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- yuki

wow, what does Dirac mean?

- anonymous

It is the Dirac Delta function.

- anonymous

It is related to the Laplace Transforms of Impulse Functions.

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- anonymous

Is it related to signal processing

- anonymous

It definitely has it's applications in that. I'm using it in differential equations right now.

- anonymous

This is way too advanced for me

- yuki

I would love to help but I don't have my DE book with me
sorry

- anonymous

no problem, thanks anyways.

- yuki

All I can remember is that all Laplace transformations have a table and it should tell you what the integral is, right?

- yuki

I hope you can find someone who can help you

- anonymous

Yes it is in there; however, I don't know what to do with it since the "cos(t)" function is slipped in there.

- yuki

integration by parts maybe?

- anonymous

I found a solution to my problem..it was quite simple. I don't have a formal proof, but Sal from Kahn Academy in his D.E. lectures justified it for me.
L{Dirac(t-c)*f(t)} = exp(-sc)*f(c)
Thanks anyways, though.

- yuki

I'm glad that you got the answer.

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