\[^{4}\sqrt{5x-9}=5\]

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\[^{4}\sqrt{5x-9}=5\]

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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5x-9=25.25 5x = 25.25 + 9 x = 5.25 + 9 x = 125+9 = 134
ack..forgot somethin
x = 125 + 9/5 lol

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125 + 1' 4/5 126' 4/5
the = sign is supposed to be < or = too 5
how are you getting 25.25??
im sorry
amistre... lol
25.25 is lazy muliplication lol
littleice, this will be the last problem that I can help since I need to go soon ok?
ok thanks
5x-9 >= 5.5.5.5 like that?
\[^4\sqrt{5x-9} = 5\] the thing is that the left side is not a sqrt, its a 4th rt so in order to get rid of that you need to take both sides to the "4th" power
so 5x-9 = 625 5x = 634 thus x=634/5 okay?
5x -9 <= 5.5.5.5 5x <= 5.5.5.5 +9 x = <5.5.5.+ 9/5 x<= 125 + 1'4/5 x <= 126' 4/5 :)
x is between 9/5 and that upper limit
... amistre, x is an exact value.
...i undertstand your confusion; but ice modified it to include the <=
oh he did? XD
answer is 1.8 is < or = x and is < than or = to 5
sry XD

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