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anonymous
 5 years ago
sqrt x+2+sqrt x=4
lol i keep asking for help on this
anonymous
 5 years ago
sqrt x+2+sqrt x=4 lol i keep asking for help on this

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that sqrt(x) + 2 or sqrt(x+2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well if its the former, x = 1 if the latter, x =49/16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=49/16 can you explain how you got this please?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x+2} + \sqrt{x} = 4\] \[\iff \sqrt{x+2} = 4\sqrt{x} \] Squaring both sides yields: \[x+2 = 16  8\sqrt{x} + x \implies \sqrt x = \frac{7}{4} \] And squaring gives the result. Note, squaring can produce spurious roots, so we must check this back in the original equation, and see that it holds.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0168sqrt x+x can you explain that more

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(ab)^2 = a^2  2ab + b^2 let a = 4 , b = sqrt(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this a formula (ab)^2 = a^2  2ab + b^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not a formula so much  well, it is an identity, but it's more just common sense of expanding brackets.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0um one more thing\[\sqrt{x+2} +\sqrt{x4}\rightarrow \sqrt{x+2}4\sqrt{x}\] how did the sqrt of x become negative when you move it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Errr, what? That didn't happen, at all. Assuming your question was right, the 4 was never under the root... and was on the other side.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i meant \[\sqrt{x+2}+\sqrt{x} 4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im still confused .......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im still confused .......
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