anonymous
  • anonymous
Help me once again please: 3+5i ----- 1-2i
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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dumbcow
  • dumbcow
what are we solving for?
anonymous
  • anonymous
um question is "Evaluate the following"
anonymous
  • anonymous
its that thing where i^1 = i i^2 = -1 i^3 = -i i^4 = 1

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dumbcow
  • dumbcow
you could multiply by conjugate to get rid of i in the denominator \[\frac{(3+5i)(1+2i)}{(1-2i)(1+2i)}\]
anonymous
  • anonymous
then expand? the problem and solve correct?
dumbcow
  • dumbcow
yes you should get (11i -7)/5
anonymous
  • anonymous
i got the 11i-5 but where does the /5 come from?
dumbcow
  • dumbcow
when you multiply the bottom 1 -2i +2i -4i^2 1-4i^2 1-4(-1) 1+4 5
anonymous
  • anonymous
Oh so multiplying both top and bottom doesn't cancel out the bottom. I see where i missed up, thank you very much :)

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