Just for verification, can you please check my answer?
Question: 3(x+2) = 6
------
2(x+1)
my answer:
6(x^2+3x+1)
Work:
expanded first after multiplying both sides with 2(x+1).==> 6x^2+18+6==> took 6 out. to get final answer. Am i correct

- anonymous

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- anonymous

What are your instructions?

- anonymous

Solve for x... shoot that means its incomplete.

- anonymous

Yep

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## More answers

- anonymous

im stuck :( whats the next step?
i cant think of any factors of 6x^2+18x+6... ah am i not suppose to factor, and use quadratic formula?

- anonymous

Hang on, what is the equation you just posted equal to?

- anonymous

my previous post is the multiplication of both sides with 2x+2

- anonymous

You have 6x^2+18x+6=0 right now, right?

- anonymous

like (3x+6)(2x+2) = 6
=>6x^2+18+12 = 6 ==> 6x^2+18+6

- anonymous

yes = 0

- anonymous

Perfect, so then you can factor out the 6 like you did before and use the quadratic formula on what's in the parentheses

- anonymous

ok one sec.

- anonymous

ok so it would be
___ ___
3 ±√-1 and 3 ±√-1
------ -------
2 2

- anonymous

just the quadratic formula answers

- anonymous

*First one = + not ±
*Second one = - not ±

- anonymous

Can you show me how you set up the quadratic formula because I got \[(-3\pm \sqrt{5})/2\] for the answer

- anonymous

umm ok -b ± √-b - 4ac
---------------
2a
so -3±√3-4(1*1) / 2(1)
* hey im sorry but can you help me in an hour? im at work and i over procrastinated and i need to finish my work, but ill be back online within an hour or hour and a half.

- anonymous

I gotta go soon, but FYI your formula's wrong: it's supposed to be b^2-4ac under the radical

- anonymous

Oh im sorry that was a typo...in both.

- anonymous

Ah i see, i did this within my previous answer too.

- anonymous

Does that solve the problem?

- anonymous

yes, but what would my final answer look like?
6 ((-3±√-5)/2) ?

- anonymous

No, because the 6 we factored out earlier doesn't affect the final answer because if we divided both sides by 6 before using the quadratic formula, we'd get x^2+3x+2=0 since 0/6=0

- anonymous

I hope that made some sense

- anonymous

So, your final answer would be \[(-3\pm \sqrt{-5})/2\]

- anonymous

Because the 6 canceled earlier

- anonymous

hmm ok i think i understand. because we divided 6, theres no need for its return. so i would just write x = (-3±√-5)/2

- anonymous

Yes! :)

- anonymous

Unless your book/teacher want you to write the two answers separately

- anonymous

In which case it would be \[x=(-3+ \sqrt{-5})/2\] and \[x=(-3-\sqrt{-5})/2\]

- anonymous

Any more questions?

- anonymous

Umm that's all for now, i should do my work now. But thank you very much :)
I'll most likely post more questions within an hour or so to check my work so make sure i don't make mistakes like this again :p

- anonymous

Thanks again, bye

- anonymous

No prob. Bye

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