## anonymous 5 years ago Just for verification, can you please check my answer? Question: 3(x+2) = 6 ------ 2(x+1) my answer: 6(x^2+3x+1) Work: expanded first after multiplying both sides with 2(x+1).==> 6x^2+18+6==> took 6 out. to get final answer. Am i correct

1. anonymous

2. anonymous

Solve for x... shoot that means its incomplete.

3. anonymous

Yep

4. anonymous

im stuck :( whats the next step? i cant think of any factors of 6x^2+18x+6... ah am i not suppose to factor, and use quadratic formula?

5. anonymous

Hang on, what is the equation you just posted equal to?

6. anonymous

my previous post is the multiplication of both sides with 2x+2

7. anonymous

You have 6x^2+18x+6=0 right now, right?

8. anonymous

like (3x+6)(2x+2) = 6 =>6x^2+18+12 = 6 ==> 6x^2+18+6

9. anonymous

yes = 0

10. anonymous

Perfect, so then you can factor out the 6 like you did before and use the quadratic formula on what's in the parentheses

11. anonymous

ok one sec.

12. anonymous

ok so it would be ___ ___ 3 ±√-1 and 3 ±√-1 ------ ------- 2 2

13. anonymous

14. anonymous

*First one = + not ± *Second one = - not ±

15. anonymous

Can you show me how you set up the quadratic formula because I got $(-3\pm \sqrt{5})/2$ for the answer

16. anonymous

umm ok -b ± √-b - 4ac --------------- 2a so -3±√3-4(1*1) / 2(1) * hey im sorry but can you help me in an hour? im at work and i over procrastinated and i need to finish my work, but ill be back online within an hour or hour and a half.

17. anonymous

I gotta go soon, but FYI your formula's wrong: it's supposed to be b^2-4ac under the radical

18. anonymous

Oh im sorry that was a typo...in both.

19. anonymous

Ah i see, i did this within my previous answer too.

20. anonymous

Does that solve the problem?

21. anonymous

yes, but what would my final answer look like? 6 ((-3±√-5)/2) ?

22. anonymous

No, because the 6 we factored out earlier doesn't affect the final answer because if we divided both sides by 6 before using the quadratic formula, we'd get x^2+3x+2=0 since 0/6=0

23. anonymous

I hope that made some sense

24. anonymous

So, your final answer would be $(-3\pm \sqrt{-5})/2$

25. anonymous

Because the 6 canceled earlier

26. anonymous

hmm ok i think i understand. because we divided 6, theres no need for its return. so i would just write x = (-3±√-5)/2

27. anonymous

Yes! :)

28. anonymous

29. anonymous

In which case it would be $x=(-3+ \sqrt{-5})/2$ and $x=(-3-\sqrt{-5})/2$

30. anonymous

Any more questions?

31. anonymous

Umm that's all for now, i should do my work now. But thank you very much :) I'll most likely post more questions within an hour or so to check my work so make sure i don't make mistakes like this again :p

32. anonymous

Thanks again, bye

33. anonymous

No prob. Bye