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anonymous

  • 5 years ago

Just for verification, can you please check my answer? Question: 3(x+2) = 6 ------ 2(x+1) my answer: 6(x^2+3x+1) Work: expanded first after multiplying both sides with 2(x+1).==> 6x^2+18+6==> took 6 out. to get final answer. Am i correct

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  1. anonymous
    • 5 years ago
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    What are your instructions?

  2. anonymous
    • 5 years ago
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    Solve for x... shoot that means its incomplete.

  3. anonymous
    • 5 years ago
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    Yep

  4. anonymous
    • 5 years ago
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    im stuck :( whats the next step? i cant think of any factors of 6x^2+18x+6... ah am i not suppose to factor, and use quadratic formula?

  5. anonymous
    • 5 years ago
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    Hang on, what is the equation you just posted equal to?

  6. anonymous
    • 5 years ago
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    my previous post is the multiplication of both sides with 2x+2

  7. anonymous
    • 5 years ago
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    You have 6x^2+18x+6=0 right now, right?

  8. anonymous
    • 5 years ago
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    like (3x+6)(2x+2) = 6 =>6x^2+18+12 = 6 ==> 6x^2+18+6

  9. anonymous
    • 5 years ago
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    yes = 0

  10. anonymous
    • 5 years ago
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    Perfect, so then you can factor out the 6 like you did before and use the quadratic formula on what's in the parentheses

  11. anonymous
    • 5 years ago
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    ok one sec.

  12. anonymous
    • 5 years ago
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    ok so it would be ___ ___ 3 ±√-1 and 3 ±√-1 ------ ------- 2 2

  13. anonymous
    • 5 years ago
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    just the quadratic formula answers

  14. anonymous
    • 5 years ago
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    *First one = + not ± *Second one = - not ±

  15. anonymous
    • 5 years ago
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    Can you show me how you set up the quadratic formula because I got \[(-3\pm \sqrt{5})/2\] for the answer

  16. anonymous
    • 5 years ago
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    umm ok -b ± √-b - 4ac --------------- 2a so -3±√3-4(1*1) / 2(1) * hey im sorry but can you help me in an hour? im at work and i over procrastinated and i need to finish my work, but ill be back online within an hour or hour and a half.

  17. anonymous
    • 5 years ago
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    I gotta go soon, but FYI your formula's wrong: it's supposed to be b^2-4ac under the radical

  18. anonymous
    • 5 years ago
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    Oh im sorry that was a typo...in both.

  19. anonymous
    • 5 years ago
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    Ah i see, i did this within my previous answer too.

  20. anonymous
    • 5 years ago
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    Does that solve the problem?

  21. anonymous
    • 5 years ago
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    yes, but what would my final answer look like? 6 ((-3±√-5)/2) ?

  22. anonymous
    • 5 years ago
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    No, because the 6 we factored out earlier doesn't affect the final answer because if we divided both sides by 6 before using the quadratic formula, we'd get x^2+3x+2=0 since 0/6=0

  23. anonymous
    • 5 years ago
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    I hope that made some sense

  24. anonymous
    • 5 years ago
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    So, your final answer would be \[(-3\pm \sqrt{-5})/2\]

  25. anonymous
    • 5 years ago
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    Because the 6 canceled earlier

  26. anonymous
    • 5 years ago
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    hmm ok i think i understand. because we divided 6, theres no need for its return. so i would just write x = (-3±√-5)/2

  27. anonymous
    • 5 years ago
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    Yes! :)

  28. anonymous
    • 5 years ago
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    Unless your book/teacher want you to write the two answers separately

  29. anonymous
    • 5 years ago
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    In which case it would be \[x=(-3+ \sqrt{-5})/2\] and \[x=(-3-\sqrt{-5})/2\]

  30. anonymous
    • 5 years ago
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    Any more questions?

  31. anonymous
    • 5 years ago
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    Umm that's all for now, i should do my work now. But thank you very much :) I'll most likely post more questions within an hour or so to check my work so make sure i don't make mistakes like this again :p

  32. anonymous
    • 5 years ago
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    Thanks again, bye

  33. anonymous
    • 5 years ago
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    No prob. Bye

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