A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Mini

  • 5 years ago

fxy if f(x,y) = (xy)^(1/2)-1/(x^2*y)

  • This Question is Closed
  1. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what would you want to do?

  2. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its double der

  3. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x then y

  4. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, so you are finding \[f_{xy}\]

  5. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  6. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its just really long wanted to see someone else do it lol

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    derivate everything to respect x and then derivate that answer to respect y

  8. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let me re-write the eqn first, it's tough to see it (xy)^(1/2)-1/(x^2*y) \[{(xy)^{1/2} \over x^2y}\]

  9. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    am I right?

  10. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    already know that brain but thank you

  11. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ill write what i have first

  12. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ill write what i have first\[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hmm.. it's going to be a quotien rule with two product rules. sorry but i'm kinda lazy to actualy write it

  14. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    quotient? i just did two product rules...

  15. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what you should notice first is that the equation is equivalent to \[\sqrt{1 \over yx^3}\]

  16. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    this is a lot easier to find the derivatives

  17. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i do chain rules and product, u dont have to use quotient

  18. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, just to let you know the quotient rule makes these problems far more faster, although I know that it is a pain. so I will just do this one with quotient rule and you try to confirm it with product rule, ok?

  19. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well product and quotient are the same thing though lol, its like comparing addition of negatives and subtraction

  20. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you are missing a -1 on the top part -> (xy)^(1/2)-1/(x^2*y): \[(\sqrt{xy}-1)\div(x^{2}y)\]

  21. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    to find f_x, I will write f as follows \[{1 \over \sqrt y} * {1 \over x^{3/2}}\]

  22. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    dont see what im missing i might of had a typo but my dx is + to the neg 2

  23. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Brain, nice catch, I was going to solve the problem not knowing that lol

  24. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha yea, sorry i was trying to type on the "Equation" thing it took me a while lol

  25. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then f = \[\sqrt{xy} - {1 \over x^2y}\]

  26. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yuki i honestly have no idea what you are doing, im changing everything to exponents then doing chain and products, it might be "slower" but its faster for myself

  27. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i mean chain is pretty simple, bring to the front, copy, minus 2, der of inside

  28. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then f_x is \[{\sqrt{y} \over 2\sqrt{x}}+{2 \over yx^3 }\]

  29. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    minus 1 even

  30. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah thats not what i got .5(xy)^(-1/2)y

  31. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well the first time with respect to x

  32. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now f_xy is \[{1 \over 4\sqrt{xy}} - {2 \over x^3y^2}\]

  33. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok. Mini, what i got so far was: Fx = \[(-2(\sqrt{xy}-1))\div(x^{3}y)\] Fxy = \[(2\times(\sqrt{xy}-1))\div(y^{2}x ^{3})\]

  34. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  35. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then product x2

  36. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for respect to y

  37. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I am 100% sure with my answer

  38. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I heard product rule, but you don't have to use it anywhere. at least I didn't

  39. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for respect to y\[-.25(xy)^{-3/2}xy+.5(xy)^{-1/2}-2(x ^{2}y)^{-3}2x ^{3}y+(x ^{2}y)^{-2}2x\]

  40. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, when you find the partial derivative of x, y is not considered a function of x, so you do not use the product rule

  41. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so its not fx*fy

  42. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so for the same reason we don't do chain rule as well

  43. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no, you dont multiply both derivatives

  44. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but why is it not in this case? its with respect to y

  45. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you take the derivate to respect x first to get Fx, then you take the derivate to respect y for the new functions whch will turn into Fxy

  46. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f_xy means \[f_{xy} = d/dy(d/dx (f))\]

  47. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  48. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes i know that much but if we are talking in terms of y, y isnt .25(xy)^(-3/2)y considered two?

  49. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like y times the other part

  50. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats just like saying in terms of x(3-x)

  51. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so you take the derivative of f in terms of x while y is constant and derivative of f_x in terms of y while x is constant

  52. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its the same thing if instead you do x^3, as x times x^2, is it not?

  53. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the last part is in terms of y, which applies to both parts so im still missing why i cant do the product once i did fx

  54. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    rather respect to y

  55. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its the same thing if instead you do x^3, as x times x^2, is it not?

  56. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that question still holds

  57. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, Are yu asking why can't you multiply fx and fy separatly?

  58. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, was my f(x,y) correct? I'm wondering because you don't seem to have any interest in what I said.

  59. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like: Fx * Fy

  60. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    im asking why i cant just do \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  61. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and to the product on that, and i dont know yuki, im not worried about the answer im worried about the concept

  62. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    not trying to be a wingspan, plus i dont even have the answer haha

  63. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, because y is not a function of x. You do not do product rule with partial derivatives because in partial derivatives, other variables are constant

  64. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so let me give you an example

  65. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but why is that not the same as x*x^2 = x^3

  66. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let's say f(x,y) = \[3x^2y\]

  67. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and separating those and doing one by product and one by chain

  68. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    6xy

  69. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then 6x

  70. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f_x would be yes, 3y*(x^2)' = 6xy

  71. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f_y would be 3x^2

  72. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f_xy and f_yx must be the same, so let's check f_xy = 6x(y)' = 6x f_yx = 3(x^2)' = 6x yay

  73. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well yeah i follow that, thats easy lol

  74. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    There's no need to do chain rule in this problem

  75. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If you would like me to answer your question why (x^3)' and (x*x^2)' are not the same they actually are

  76. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ah there might be no NEED, but can i do it that way

  77. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its my train of thought, thats all i can say

  78. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and i know they are the same, thats what im basing my principle on just doing the product rule on

  79. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (x*x^2)' is x'*x^2 + (x^2)'*x =x^2+2x*x =3x^2

  80. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  81. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats my in terms of x

  82. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay now I think we are on the same page, so you are trying to use the product rule for this problem anyways, am I right ?

  83. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    my question still stands why i cant do the product rule on this

  84. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes!!!

  85. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    MIni, you can use the product rule

  86. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and that equation is now going to be derived in terms of y

  87. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay, gotcha. just to let you know that is very unorthodox, and I haven't tried it yet, so give me some time to work it out first.

  88. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha, thats what my professor said, i know he loves grading my papers but i see everything as addition and multiplication

  89. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hehe okay, yea, you can do product rule but yu still have to do another quotien rule

  90. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you will have to do two product rules inside a quotien rule

  91. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    mini, I want to know how you will consider f(x,y)

  92. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where? once i do the product for \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  93. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    on both sides isnt it just two products?

  94. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    isn't the main equation a fraction?

  95. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no, i changed them into multiplication

  96. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you type the main equation and your "changed" equation? please

  97. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sqrt(xy)-1/(x^2*y)

  98. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes that's the main, now what did yu change that for?

  99. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    changed to (xy)^(1/2) - (x^2y)^-1

  100. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, this is your f(x,y) \[\sqrt{xy}-{1 \over x^2y}\] what do you want to do from here ? without that I cannot tell what you are doing

  101. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    both of you that before u jus typed is what i changed it to, and i changed it just to do the chain because its easier for myself

  102. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Mini, if that is your claim it doesn't look right in the first place

  103. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and ignore the bad parathesis i just didtn want to put them all up, im pretty sure you followed it

  104. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, even thou you changed the equation for two multiplication instead a fraction. There is no chain rule in that equation

  105. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (xy)^(1/2) isnt a chain rule lol? one half goes tot he front, leave xy, minus 1, then put y outside because its in terms of x?

  106. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    did you want to wright it as \[x^{1/2}y^{1/2} -x^{-2}y^{-1}\] ?

  107. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no, you are taking the derivative to respec x which makes y into a constant. it's same as taking the derivative of (x3)^(1/2)

  108. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no, thats fine too its the same thing, u just multiplied the -1 out

  109. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes thats why y is still on the outside, its the constant...when u do the der of the inside

  110. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it would be (1/2)(y)(xy)(-1/2) is that right

  111. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes well to the negative half

  112. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (1/2)(y)(xy)^(-1/2) ops,

  113. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it might be unorthodox like yuki said but thats how i did it

  114. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yea but, it would work. i don't see why it wouldn't

  115. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like i get my \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  116. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and that was in terms of x

  117. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now i just do products in terms of y

  118. Yuki
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay Mini, I cannot help you unless you answer me so... just let me know if you are ready to focus. I'm pretty sure there are others who can help.

  119. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont know what question you asked yuki?

  120. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if you mean if i wanted to write it as...i did answer you...

  121. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    damn yo you typing a lot, scaring me!

  122. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    F = (xy)^(1/2) - (x^2y)^-1 Fx = .5y(xy)^(-1/2) + 2xy(x^2y)^-2) Fxy = .5(xy)^(-1/2) + .5y(-.5(xy)^(-3/2) + 2x(x^2 y)^(-2) + 2xy(-2x^2(x^2y)^(-2))

  123. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh pellet no wonder you were tying a long time, thought he chat froze haha

  124. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if yu can understand my Fxy.. that's what i got lol

  125. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha yea.. this chat thing kinda sucks

  126. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ill start from the begin then

  127. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like of what you posted not the real begin

  128. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    −.25(xy)−3/2xy+.5(xy)−1/2−2(x2y)−32x3y+(x2y)−22x ?

  129. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    should be xy on the first one

  130. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    at the end of mine the two last parts canceled out, and i was only left iwth the first 2

  131. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    xy on 2nd one***

  132. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    should be -.25(xy)^(-3/2)xy

  133. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    last ones i think looks good too, i just missed the 4 when i was simplifying, which doesnt cancel but just reduces

  134. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ill just post it one product at a time

  135. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then im takin a break and ill be back on prob in an hour! lol

  136. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  137. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think i'm using the wrong equation lol is the main equation this : (xy)^(1/2)-1/(x^2*y) ?

  138. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  139. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no u have the right one, and we are dead one together but i think u messed up the first product rule

  140. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    [ (xy)^(1/2) ] - [ 1/(x^2*y)] ?

  141. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    when u derive .5(xy)^(-1/2)y

  142. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but derive the first "function" not y

  143. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats where our answers are different

  144. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u should get one fourth xy to the neg 3/2 then times x, then also times y from the orig

  145. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    right? haha its almost easier writing it out instead of using that dumb equation thing

  146. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so your Fxy is: (.5) * (((.5) - 1) * (x * y) ^ (((.5) - 1) - 1) * x * y + (x * y) ^ ((.5) - 1)) + 2 * x * ((x ^ 2 * y) ^ 2 - y * 2 * (x ^ 2 * y) * x ^ 2) / (x ^ 2 * y) ^ 2 ^ 2

  147. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh wow my brain just died after seeing that

  148. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    one at a time yo! one at a time!

  149. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    haha i just used a partial derivative calcualtor

  150. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.calculator-grapher.com/derivative-calculator.html

  151. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[.5(xy)^{-1/2}y+(x ^{2}y)^{-2}2xy\]

  152. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay thats what we are doing in terms of y

  153. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so im going to product the difference of them, 1 product then another

  154. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    or sum of them w/e

  155. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the first product i get \[-.25(xy)^{-3/2}xy+.5(xy)^{-1/2}\]

  156. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh im using copy paste, makes it ALOT easier haha

  157. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the second product is \[-2(x ^{2}y)^{-3}2x ^{3}y+(x ^{2}y)^{-2}2x\]

  158. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Fx = (.5)y(xy)^(.5) + 2xy/(x^2y)^2 Fxy = (.25)(y^2) / (sqrt(xy)) - 6/(x^4*y)

  159. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol

  160. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    eh close enough

  161. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh well.. i'm out lol good luck

  162. Mini
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks man! have a good one

  163. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    np y too

  164. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.