anonymous
  • anonymous
in preparation for the final exam, which counts as two exams, a student has scores of 88,97, and 91. what does the student need on the final exam to have a 90 average?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
(88.97+91+x)/3=90 180-88.97-91=x
anonymous
  • anonymous
missed out a term mr stats major :P
anonymous
  • anonymous
oopsies, please correct me, mr. troll :D

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anonymous
  • anonymous
oh wow, I was reading that as 88.97; der... should be (88+97+91+x)/4=90 360-88-97-91=x=84
anonymous
  • anonymous
no, well I guess you didnt miss out a term, but you read the first term as 88.97 , ill bet ohh I dont know $1000 that they meant it to be two seperate terms now mr stats major, what would be my chances of being correct and taking your money :D
anonymous
  • anonymous
@elecengineer: lol, you sure it was 8,897?
anonymous
  • anonymous
ohh dont worry, you are only a dumb stats major with no real use to society , just play around with lots of numbers and probabilities, so boring
anonymous
  • anonymous
hahahhahah we both got it wrong; the final counted as two exams brosky: (88+97+91+2x)/5=90
anonymous
  • anonymous
u mean you got it wrong
anonymous
  • anonymous
and you didn't help ;)

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