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anonymous

  • 5 years ago

in preparation for the final exam, which counts as two exams, a student has scores of 88,97, and 91. what does the student need on the final exam to have a 90 average?

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  1. anonymous
    • 5 years ago
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    (88.97+91+x)/3=90 180-88.97-91=x

  2. anonymous
    • 5 years ago
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    missed out a term mr stats major :P

  3. anonymous
    • 5 years ago
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    oopsies, please correct me, mr. troll :D

  4. anonymous
    • 5 years ago
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    oh wow, I was reading that as 88.97; der... should be (88+97+91+x)/4=90 360-88-97-91=x=84

  5. anonymous
    • 5 years ago
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    no, well I guess you didnt miss out a term, but you read the first term as 88.97 , ill bet ohh I dont know $1000 that they meant it to be two seperate terms now mr stats major, what would be my chances of being correct and taking your money :D

  6. anonymous
    • 5 years ago
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    @elecengineer: lol, you sure it was 8,897?

  7. anonymous
    • 5 years ago
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    ohh dont worry, you are only a dumb stats major with no real use to society , just play around with lots of numbers and probabilities, so boring

  8. anonymous
    • 5 years ago
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    hahahhahah we both got it wrong; the final counted as two exams brosky: (88+97+91+2x)/5=90

  9. anonymous
    • 5 years ago
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    u mean you got it wrong

  10. anonymous
    • 5 years ago
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    and you didn't help ;)

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spraguer (Moderator)
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