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anonymous

  • 5 years ago

One more problem: A train leaves a station and travels at the rate of 40 mi/hr. Two hours later a second train leaves the station and travels at the rate of 60 mi/hr. Where will the second train overtake the first?

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  1. anonymous
    • 5 years ago
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    from the first train (A) we have: S=So+Vo(t) S=0+40(t) after two hours (when second train leaves) train A has traveled: S=40(2) S=80 In relation to the second train (B), train A starts at 80 so, rearranging Train A's eqt: Sa = 80 + 40(t) And from train B we have: Sb = 0 + 60(t) ! The second train will overtake the first whenever Sa=Sb so, 80 + 40(t) = 60 (t) 20 (t) = 80 t = 80/20 = 4hr Ans. Is tha right?

  2. anonymous
    • 5 years ago
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    No, they want to know the place. Where will the second train overtake the first, not the duration.

  3. anonymous
    • 5 years ago
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    oh misread the question, sorry. you still have to make those calculations. With how much time they take to meet you plug it back in either equation A or B and it should give you the same answer: Sa = 80 + 40 (4) Sa = 80 + 160 = 240 mi Sb = 60 (4) = 240 mi So, The second train will overtake the first 240mi from the station

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