One more problem: A train leaves a station and travels at the rate of 40 mi/hr. Two hours later a second train leaves the station and travels at the rate of 60 mi/hr. Where will the second train overtake the first?
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from the first train (A) we have:
S=0+40(t) after two hours (when second train leaves) train A has traveled:
In relation to the second train (B), train A starts at 80 so, rearranging Train A's eqt:
Sa = 80 + 40(t)
And from train B we have:
Sb = 0 + 60(t)
! The second train will overtake the first whenever Sa=Sb so,
80 + 40(t) = 60 (t)
20 (t) = 80
t = 80/20 = 4hr Ans.
Is tha right?
No, they want to know the place. Where will the second train overtake the first, not the duration.
oh misread the question, sorry.
you still have to make those calculations. With how much time they take to meet you plug it back in either equation A or B and it should give you the same answer:
Sa = 80 + 40 (4)
Sa = 80 + 160 = 240 mi
Sb = 60 (4) = 240 mi
So, The second train will overtake the first 240mi from the station