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anonymous
 5 years ago
Help with rationalizing denominators
equation is 1 over the square root 96
not sure what to do
anonymous
 5 years ago
Help with rationalizing denominators equation is 1 over the square root 96 not sure what to do

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1 FRACTION \sqrt{96}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/\sqrt{96} \times \sqrt{96}/\sqrt{96} = \sqrt{96}/9\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/\sqrt{96}\]\[\sqrt{96}/(\sqrt{96}*\sqrt{96})\]\[\sqrt{96}/96\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understand I have to write the smallest number of a perfect square, but unsure of how to water that down. haha

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01 is the numerator. 96 is the denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0962 482 242 122 062 033 01 \[\sqrt{2^{5}*3}=4\sqrt{2*3}=4\sqrt{?}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4\sqrt{6}/96 = \sqrt{6}/\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would you mind explaining it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to simplify a sqrt, you devide the number by primary numbers: 2,3,5,7,11,13,... until you get 1. The amount of primary is the amount of times you are multiplying it so as i did: 962 96/2 = 48 482 48/2 = 24 242 24/2 = 12 122 12/2 = 06 062 06/2 = 03 033 i can't devide 3 by 2 to get a nondecimal number so, i devide by the next primary which is 3 > 03/3 = 1 01 I have five 2's and one 3 therefore, 2^5*3 = 96

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2^{5}*3^{1} = 2^{2}*2^{2}*2^{1}*3^{1} = 96\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I somewhat get it a bit better.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Times both the numerator and denomiator by \[\sqrt{96}\] to get \[1*\sqrt{96}/\sqrt{96}*\sqrt{96}\] Then the denominator becomes 96 and the numerator becomes \[\sqrt{96}\] You then can simplify the numerator; \[\sqrt{96} = \sqrt{16*64} =4\sqrt{6}\] As now both the numerator and denominator are divisible by 4 we can divide them both to make \[\sqrt{6}/24\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what should the answer look like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah, I got it. I am just hazy on the whole find 1 thing that you mentioned earlier. how did you determine 16 and 64 for the square roots of 96??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is the smallest surd you can get ; \[\sqrt{6}\] over the smallest integer you can get; 24 which equates to \[\sqrt{6}/24\] ^^^ that's your answer..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0got that. so I have 10 over square root of 45 first step, mult 45 by 45

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OH DEAR>> I meant 16*6 not *64.. my computer is very slow so i can't see my errors in typing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so is it that 6 is the smallest square root, and 16 is because it goes into 96 6 timesleaving a relation between 6 and 16?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhhkay cool. thanks dude!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what if it has a factored numerator?such as \[\sqrt{6}/\sqrt{28}\]
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