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\[1 FRACTION \sqrt{96}\]

\[1/\sqrt{96} \times \sqrt{96}/\sqrt{96} = \sqrt{96}/9\]

\[1/\sqrt{96}\]\[\sqrt{96}/(\sqrt{96}*\sqrt{96})\]\[\sqrt{96}/96\]

1 is the numerator. 96 is the denominator

96|2
48|2
24|2
12|2
06|2
03|3
01|-
\[\sqrt{2^{5}*3}=4\sqrt{2*3}=4\sqrt{?}\]

2?

\[4\sqrt{6}/96 = \sqrt{6}/\]

\[\sqrt{6}/24 \]

would you mind explaining it?

in english haha

\[2^{5}*3^{1} = 2^{2}*2^{2}*2^{1}*3^{1} = 96\]

I somewhat get it a bit better.

what should the answer look like?

got that. so I have 10 over square root of 45
first step, mult 45 by 45

OH DEAR>>
I meant 16*6 not *64..
my computer is very slow so i can't see my errors in typing

yeah :)

ohhhkay cool. thanks dude!

what if it has a factored numerator?such as \[\sqrt{6}/\sqrt{28}\]