A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Please give an easy and fast way to solve this:
anonymous
 5 years ago
Please give an easy and fast way to solve this:

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x ^{2}xc2c ^{2}=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the quadratic formula.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(a+b^{2}=a ^{2} + 2ab + b ^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but isn't' a quadratic equation of the type: \[a ^{2}+2ab+b ^{2}=0\] OR \[a ^{2}2ab+b ^{2}=0\] My equation has two ve signs.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to get x = 2c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please show the steps.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2−xc−2*c^2=0 (x+c)(x2c)=0

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0\[x = {c \pm \sqrt{c^2  4*z*(2c^2)} \over 2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^2x c2c^2=0 x=c+sqrt(c^24*1*2c^2)/2*1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0c can be treated as a constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^{2}xcc ^{2}=x^{2}2xc+xcc ^{2}=(x2c)(x+c)=0 so we have x=2c or x=c\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.