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anonymous
 5 years ago
Why is the radius or distance from axis of rotation squared as in \[I = mr_{cm}^2 \]
anonymous
 5 years ago
Why is the radius or distance from axis of rotation squared as in \[I = mr_{cm}^2 \]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its a rotational analogue to mass (inertia) drawn from the equation for torque

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0F=ma T=Fr Fr = mar a=r(alpha) hence T=mr^2 (alpha)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0T is to force what alpha is to a, hence the analogue of mass is the moment of inertia (mr^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is because in rotational mechanics the mass is equivalent to the moment of inertia. and the term r is squared because I is moment of inertia and the axis of rotation if taken along some axis then the distance should be positive. theoretically...
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