anonymous
  • anonymous
The length of a rectangle is 8 meters more than its width. If the area is 65 square meters, what are the length and width?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Let x= width Let y = length y = 8 + x Area = length x width A = (8+x)(x) 65 = (8+x)(x) 65 = 8x+x^2 0 = x^2 + 8x -65 I don't think it works out perfectly but try solving that
anonymous
  • anonymous
hmm...
anonymous
  • anonymous
would it be (x+13)(x-5) or no?

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anonymous
  • anonymous
Yes! Haha I didnt think it'd be a perfect polynomial but it does work out! The width is 5 (since the width cant be negative) and then the length is 13.

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