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anonymous
 5 years ago
A 10ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge. The horizontal distance that it spans is 2 ft longer that the height that it reaches on the side of the bridge. Find the horizontal and vertical distances spanned by this brace.
anonymous
 5 years ago
A 10ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge. The horizontal distance that it spans is 2 ft longer that the height that it reaches on the side of the bridge. Find the horizontal and vertical distances spanned by this brace.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, is there an image?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0damn lol I can't think right now, but if you had an image of it then it'll make my job easier :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The width of a rectangular gate is 2 meters (m) larger than its height. The diagonal brace measures √6m. Find the width and height.  Draw the picture Let the height be "x" meters Then the width is "x+2" meters  Draw the diagonal = sqrt(6) meters  EQUATION: Use Pythagoras to solve for "x": x^2 + (x+2)^2 = [sqrt(6)]^2 2x^2 + 4x + 4 = 6 2x^2 + 4x 2 = 0 x^2 + 2x 1 = 0  Use the Quadratic Formula: x = [2 + sqrt(4 4*1*1)]/2 x = [2 + sqrt(8)]/2 Positive solution: x = [2 + 2sqrt(2)]/2 x = [1 + sqrt(2)] x = 0.414 meters (height of the rectangle) x+2 = 2.414 meters (width of the rectangle) ============================== Found it here  The width of a rectangular gate is 2 meters (m) larger than its height. The diagonal brace measures √6m. Find the width and height.  Draw the picture Let the height be "x" meters Then the width is "x+2" meters  Draw the diagonal = sqrt(6) meters  EQUATION: Use Pythagoras to solve for "x": x^2 + (x+2)^2 = [sqrt(6)]^2 2x^2 + 4x + 4 = 6 2x^2 + 4x 2 = 0 x^2 + 2x 1 = 0  Use the Quadratic Formula: x = [2 + sqrt(4 4*1*1)]/2 x = [2 + sqrt(8)]/2 Positive solution: x = [2 + 2sqrt(2)]/2 x = [1 + sqrt(2)] x = 0.414 meters (height of the rectangle) x+2 = 2.414 meters (width of the rectangle) ============================== Found it here  The width of a rectangular gate is 2 meters (m) larger than its height. The diagonal brace measures √6m. Find the width and height.  Draw the picture Let the height be "x" meters Then the width is "x+2" meters  Draw the diagonal = sqrt(6) meters  EQUATION: Use Pythagoras to solve for "x": x^2 + (x+2)^2 = [sqrt(6)]^2 2x^2 + 4x + 4 = 6 2x^2 + 4x 2 = 0 x^2 + 2x 1 = 0  Use the Quadratic Formula: x = [2 + sqrt(4 4*1*1)]/2 x = [2 + sqrt(8)]/2 Positive solution: x = [2 + 2sqrt(2)]/2 x = [1 + sqrt(2)] x = 0.414 meters (height of the rectangle) x+2 = 2.414 meters (width of the rectangle) ============================== I found it on a website. I have no rights to this solution. Hope it helps!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, I'm not sure of my answer, but that's what I ended up with ^_^ :  bridge = rectangular shape.  diagonal is half way through the rectangle of length = 10ft  L = 2 + x  w = x. >_< LOL! I was abt to say this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you for your help LF ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+2)^2 + x^2=100. would that be right so far. buecause i am never good with these problems and never have been.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then i have 2x^2+2x+4=100. is that right or am i way off.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x+2)^2 + x^2=100 \] = \[x^2 + 4 + 2(x)(2) + x^2 =100 \] using, \[(a + b) ^2 = a^2 + b^2 +2ab\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then how would i go from there? never done a problem like this for awhile.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its a quadratic eqn in x..solve it for x using the quadratic formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02x^2 + 4x 96=0 so x^2 +2x 48=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 8 feet and 6 feet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use this formula, \[ax^2 + bx + c = 0\] \[=> x = b \pm \sqrt{b^2 4ac} / 2a\] the 2a term is dividing the entire term of \[b \pm \sqrt{b^2 4ac} \]
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