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Can someone set these word problems up so that I can solve for the answer.
1. One canned juiced drink is 20% orange juice; another is 10% orange juice. How much many liters of each should be mixed together in order to get 10L that is 18% orange juice?
How many liters of the 20% orange juice should be in the mixture?
How many liters of the 10% orange juice should be in the mixture?
 2 years ago
 2 years ago
Can someone set these word problems up so that I can solve for the answer. 1. One canned juiced drink is 20% orange juice; another is 10% orange juice. How much many liters of each should be mixed together in order to get 10L that is 18% orange juice? How many liters of the 20% orange juice should be in the mixture? How many liters of the 10% orange juice should be in the mixture?
 2 years ago
 2 years ago

This Question is Closed

LfcmaniacBest ResponseYou've already chosen the best response.1
Well what I guess is that this problem has infinitely many solutions! You get only ONE equation which has TWO variables. So obviously there are many many solutions to it. The equation is  20% (X liters) + 10% (Y liters) = 18% (10L) where X and Y are the amount of total juice in the two cans respectively. I am giving you a few possible solutions  X = 1.6L Y = 2L X = 5L Y = 8L etc. Hope that helps!
 2 years ago
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