## anonymous 5 years ago How to solve abs(e^(2x) - (1/x+2)) = 2

1. anonymous

$| e ^{2x} - 1/(x+2)| = 2$ absolute value mean that it's =( 2 ) or =( -2 ) so, solve for both and you'll have yur answer. got it ?

2. anonymous

yea i'm trying to do that, but i'm not really getting anywhere

3. anonymous

Ok. So, for the first equality: $e ^{2x} - 1/(x+2) = 2$ you can take out the fraction by inverting everything:$e^{-2x} - (x+2) = 1/2$$e^{-2x} - x = 5/2$ to eliminate the {e}, multiply everything by Natural Log (ln)$-2x - \ln x = \ln (5/2)$ solve for x and there might be more than 1 solution

4. anonymous

how do i go on from -2x = ln (5x/2)

5. anonymous

sorry, i can't remember/find how to solve :/

6. anonymous

aw it's ok, thanks for your help though :)

7. anonymous

np, if i find somewhere i'll post it here (: