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anonymous
 5 years ago
I need to find the flux through a disk of radius 1 centered at (1,1,1) with its normal pointing towards the origin. How do i parameterize this disk?
anonymous
 5 years ago
I need to find the flux through a disk of radius 1 centered at (1,1,1) with its normal pointing towards the origin. How do i parameterize this disk?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found that it lies in the plane xyz=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0should i take the intersection between this plane and a sphere centered at 111

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find a vec tor normal to it, with magnitude of the area of the disk

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats the vec tor field??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I cant use divergence theorem right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats whts confusing me..no i dont think divergence thm is applicabe..old way then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah so i need a parametric surface

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats wht i really dunno..;.parametrizing surfaces

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can find the intersection between the sphere and a plane but its an ugly integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know theres another way to do it using tangents to the normal but i cant remember

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well the disk lies in the plane xyz=3 and theres a sphere with rad 1 cestered at (1.1.1) of the form <rcos(theta)sin(phi), rsin(theta)sin(phi), rcos(phi)>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0go on.bt watll u do wid d sphere?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im trying to figure it out i cant remember exactly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know paramet for cylinders and all bt nt this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Using vectors, generally if t is the parameter then and point P on the circle is given by; LaTeX Code: P = R\\cos(t) \\vec{u} + R\\sin(t) \\;\\;\\vec{n}\\times\\vec{u} + c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0check this out: http://www.physicsforums.com/showthread.php?t=123168

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need 2 parameters for surfaces

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0go down to the post where it writes a parametric eqn for a circle in 3d..our surface is actually a circle at some angle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0uve got t and the vector u here as parameters

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u add u the components of i,j,k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0kool ill try the eq on that link

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u get x,y,z in terms of t and u

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think thatll parametrize it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0U is an orthognal vector not a parameter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0t and r are the parameters

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0r is the radius mate...u is the parametric vector from the centre to that point and n is the orthogonal vector

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you use polar coords?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to integrate over the radius to get a disk

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats how far i cn get at parameterizing it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i g2g.. i learnt a lot thru this discusion..thnx..hope u get it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0polar is the way to go, I'm not sure what him1618 meant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its in 3 space so its in cylindrical

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just have z=z be one condition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if z doesn't vary, well i guess cylindrical still applies, anyway the jacobian is still r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but z does change the disk is tilted in 3 dimentions
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