A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
In(x+1)In(x)=1 i know the answer is 1over e1 but how?
anonymous
 5 years ago
In(x+1)In(x)=1 i know the answer is 1over e1 but how?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I rearranges it: ln(x+1)=1+ln(x) Substitute 1=ln(e) and use the properties of logarithms to get ln(x+1)=ln(ex) So x+1=ex Solve for x

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0I recommend this way , too \[e^{\ln(x+1)\ln(x)}=e^1\] by taking both sides to the exponent

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0so by property of exponents, \[{e^{\ln(x+1)} \over e^{\ln(x)} } =e\] and by definition of logarithm, \[{x+1 \over x} = e\]

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0so by cross multiplication x+1 = ex xex = 1 x(1e) = 1 x =\[1 \over 1e\]

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0if you multiply 1/1 to make the top = 1, \[1 \over e1\]

Yuki
 5 years ago
Best ResponseYou've already chosen the best response.0let me know if there is anything that you didn't get

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey Yuki if you could please elaborate a little on this part  " \[e^{\ln(x+1)}\div e^{\ln(x)}=e\] and by definition of logarithm, x+1/x = e" How do you end up on the second equation from the first?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.