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anonymous
 5 years ago
4x^2 +24x+35=0
anonymous
 5 years ago
4x^2 +24x+35=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need to factor...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = \[24 \pm \sqrt{24^24(4)(35) }\] \[/2(4)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good call, use the quadratic equation for that. You could, however, factor that. 35 has the following primes: 5, 7. 24 has the following primes: 2,2,2,3, and 4 has two primes, 2,2. Don't think this will factor into easy integers, so just use quadratic equation here.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Doesn't look like it factors easily, so use completing the square: \[4x ^2+24x +35 = 0\] (Divide by the xsquared coeficient) \[x ^2+6x +35/4 = 0\] (Move the constant term to the other side) \[x ^2+6x = 35/4\] (Take half the coeficient of the x term, square it, and add to both sides) \[x ^2+6x +3^2 = 35/4 +3^2\] (Now the left side of the equation is a perfect square, and factors easily) \[(x +3)^2 = 35/4 +9\] (take the square root of each side) \[x +3 = \pm\sqrt{35/4 +9}\] (now just move the three over, and you're done) \[x =3 \pm\sqrt{35/4 +9}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ends up reducing to 5/2 and 7/2
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