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yes
let's find f_x first

When you take the partial derivative with respect to x, consider y as a constant.

\[f = e^{x^2} + xy \]
\[f_x = 2x*e^{x^2} + y\]

\[{\partial z \over \partial x}=2xe^{x^2}+y\]

\[f_y = 0 + x = x\]

\[{\partial z \over \partial y}=x\]

Anwar you always surprise me.
How did you get that "d" from ?!

Anwar you always surprise me.
How did you get that "d" from ?!\[\partial\]

Try to find out yourself :)

cool !!!

lol that was fast :)

that was a lot easier than I thought lol

Haha yeah

so it is actually not that hard.
implicit differentiation is much more harder :)

it means u simply have to separate out the e^x ?