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anonymous

  • 5 years ago

2 cos 3x - 1 = 0

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  1. anonymous
    • 5 years ago
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    2cos 3x=1 Work it like any other equation

  2. anonymous
    • 5 years ago
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    cos (3x) = 1/2 We know that cos(x) =1/2 when x = Pi/6, so it must be Pi/18

  3. anonymous
    • 5 years ago
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    How did you get this? Im still a bit confused :(

  4. anonymous
    • 5 years ago
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    Solve 2cos(3x)-1=0 for cos(3x) this gives you: cos(3x)=1/2 as software said previously, we know that cos(x)=1/2 @ x=pi/6 Using this x=pi/6, replace x with 3x: 3x=pi/6 (solve for x) Voila, x=pi/18; depending on your interval (ie 0<x<pi)

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