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anonymous
 5 years ago
A 10ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge. The horizontal distance that it spans is 2 ft longer that the height that it reaches on the side of the bridge. Find the horizontal and vertical distances spanned by this brace.
anonymous
 5 years ago
A 10ft diagonal brace on a bridge connects a support of the center of the bridge to a side support on the bridge. The horizontal distance that it spans is 2 ft longer that the height that it reaches on the side of the bridge. Find the horizontal and vertical distances spanned by this brace.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is what i have so far (x + 2)^2 + x^2 = 100 X^2 +4 + 2 (x) (2) +x^2 = 100 Using, (a + b)^2 = a^2 + b^2 +2ab 2x^2 +4x 96 = 0 So x^2 + 2x 48 = 0 Its 8 feet and 6 feet. X is 6 ft. Using this formula, Ax^2 +bx +c = 0 x = b ± √(b^2 4ac)/2a 8=b±√(b^24ac)/2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from here I have no clue.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lol Look at the pythagorean thereom Ill send a pic with it Solve for y [4y^2 + y^2] = (5^1/2)*y = 10 y = 10/(5)^1/2 = 4.5 ft (vertical) and 9.0ft (horizontal)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am sorry that is a mistake...I made the horizontal distance 2 times the vertical new solution in a minute
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