anonymous
  • anonymous
find the factors 2x^4+16x^3+32x^2=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
2 x^2 (x+4)^2 x = 0, 0, -4, -4
anonymous
  • anonymous
i got something different, i didnt get -4 i got just 4
anonymous
  • anonymous
i got 2x^2(x+4)^2

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anonymous
  • anonymous
Thats what I have.
anonymous
  • anonymous
Plug in -4 into the (x+4)^2, and get 0.
anonymous
  • anonymous
The answer you are looking for is 2x^2(x+4)^2

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