anonymous
  • anonymous
Radicle 250m^3 over 2n *m and n are different, it is not a mistake.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
are they both on sqrt like this: ?\[\sqrt{250m^{3}/2n}\]
anonymous
  • anonymous
yeah, they're both radicles, except ones on top and others on bottom, not one big equation.
anonymous
  • anonymous
And you're asked to?!

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anonymous
  • anonymous
?
anonymous
  • anonymous
asked to what
anonymous
  • anonymous
\[\sqrt{250m^{3}} / \sqrt{2n}\]\[\sqrt{250m^{3}} / \sqrt{2n} * \sqrt{2n}/\sqrt{2n} = \sqrt{250m^{3}}\sqrt{2n} / 2n\]\[\sqrt{250m^{3}}\sqrt{2n} / 2n = \sqrt {500m^{3}n} \]
anonymous
  • anonymous
thx

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