anonymous
  • anonymous
Simplify. 2x^4-3x^3-11x^2-40x-1 all over x-4
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
You want to write in the form of quotient and a remainder?
anonymous
  • anonymous
sure
anonymous
  • anonymous
If so, then (using long division): \[{2x^4-3x^3-11x^2-40x-1 \over x-4}=2x^3+5x^2+9x-4-{17 \over x-4}\]

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anonymous
  • anonymous
how did u get that????
anonymous
  • anonymous
Do you know how to do long division?
anonymous
  • anonymous
yes
anonymous
  • anonymous
you have to factor the numerator, and one of those factors should be (x-4) which can cancel out.
anonymous
  • anonymous
Okay, then do it till you stop at the point where you have a reminder of -17. At this point, you will have a quotient equal to 2x^3+5x^2+9x-4. And a reminder of -17. The original expression is equal to = the quotient +the reminder/divisor.
anonymous
  • anonymous
@halcyon_m: it wouldn't work that way, since x-4 is not a factor of the numerator.
anonymous
  • anonymous
thanks

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