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anonymous

  • 5 years ago

Simplify. 2x^4-3x^3-11x^2-40x-1 all over x-4

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  1. anonymous
    • 5 years ago
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    You want to write in the form of quotient and a remainder?

  2. anonymous
    • 5 years ago
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    sure

  3. anonymous
    • 5 years ago
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    If so, then (using long division): \[{2x^4-3x^3-11x^2-40x-1 \over x-4}=2x^3+5x^2+9x-4-{17 \over x-4}\]

  4. anonymous
    • 5 years ago
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    how did u get that????

  5. anonymous
    • 5 years ago
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    Do you know how to do long division?

  6. anonymous
    • 5 years ago
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    yes

  7. anonymous
    • 5 years ago
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    you have to factor the numerator, and one of those factors should be (x-4) which can cancel out.

  8. anonymous
    • 5 years ago
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    Okay, then do it till you stop at the point where you have a reminder of -17. At this point, you will have a quotient equal to 2x^3+5x^2+9x-4. And a reminder of -17. The original expression is equal to = the quotient +the reminder/divisor.

  9. anonymous
    • 5 years ago
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    @halcyon_m: it wouldn't work that way, since x-4 is not a factor of the numerator.

  10. anonymous
    • 5 years ago
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    thanks

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