## anonymous 5 years ago Simplify. 2x^4-3x^3-11x^2-40x-1 all over x-4

1. anonymous

You want to write in the form of quotient and a remainder?

2. anonymous

sure

3. anonymous

If so, then (using long division): ${2x^4-3x^3-11x^2-40x-1 \over x-4}=2x^3+5x^2+9x-4-{17 \over x-4}$

4. anonymous

how did u get that????

5. anonymous

Do you know how to do long division?

6. anonymous

yes

7. anonymous

you have to factor the numerator, and one of those factors should be (x-4) which can cancel out.

8. anonymous

Okay, then do it till you stop at the point where you have a reminder of -17. At this point, you will have a quotient equal to 2x^3+5x^2+9x-4. And a reminder of -17. The original expression is equal to = the quotient +the reminder/divisor.

9. anonymous

@halcyon_m: it wouldn't work that way, since x-4 is not a factor of the numerator.

10. anonymous

thanks