## anonymous 5 years ago use the square root property to solve the quadratic equation (x-3)^2=4 a.x=7 b.x=1,-5 c. x=5,1 d. x=2,-2

1. anonymous

First of all: (x-3)^2=4 $\sqrt{(x-3)^{2}}= \pm \sqrt{4}$ $x-3 = \pm 2$ $\left\{ 1,5 \right\}$

2. anonymous

Taking the square root of $(x - 3)^{2}$ saves you a lot of work since 4 is a perfect square. This method is great for solving exercises like this one.

3. anonymous

thanks :)