anonymous
  • anonymous
4/x+12/x-5=-11 solve.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i multiplied by the lcd and i got the answer 5 but it was wrong not sure what im doing wrong
anonymous
  • anonymous
i multiplied by the lcd and i got the answer 5 but it was wrong not sure what im doing wrong
anonymous
  • anonymous
16/x=-6 x=-16/6=-8/3

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[\frac{4}{x}+\frac{12}{x}-5=-11\text{ }\text{ or }\text{ }\frac{ 4}{ x}+\frac{12}{x-5}=-11 \]
anonymous
  • anonymous
(4/x)+(12/x-5) =-11
anonymous
  • anonymous
(4/x)+(12/x-5) =-11
anonymous
  • anonymous
(4/x)+(12/x-5) =-11
anonymous
  • anonymous
In either case put all of the terms on the left hand side of the equation and combine the terms into one fraction. the fraction is zero therefore the numerator has to be zero. Set the numerator to = 0 and solve for x.
anonymous
  • anonymous
that explanation didnt do anything for me
anonymous
  • anonymous
(4/x) + (12/(x - 5)) = -11 Is the above the problem statement? This one is different than your last posting.
anonymous
  • anonymous
yes
anonymous
  • anonymous
yes
anonymous
  • anonymous
Good. If you bring the -11 over to the left hand side you will have: \[11+\frac{12}{-5+x}+\frac{4}{x}=0 \] The terms may be in a different order than yours, but the equation is still valid.
anonymous
  • anonymous
ok
anonymous
  • anonymous
Now when you combine all of the terms on the left hand side together, you will have the following fraction equal to zero: \[\frac{-20-39 x+11 x^2}{(-5+x) x}=0 \]
anonymous
  • anonymous
???????????????
anonymous
  • anonymous
???????????????
anonymous
  • anonymous
??????? ... I get it. You are having trouble with combining fractions. Is that right?
anonymous
  • anonymous
i dont see how you got the numerator
anonymous
  • anonymous
4(x-5)+12(x)+11x(x-5)=0 -20-39x+11x^2=0 x=4 (+/_)
anonymous
  • anonymous
my bad its only 4 next answer is -0.45
anonymous
  • anonymous
You have to find a common divisor, an expression divisible by all of the denominators. A common divisor of 1, x-5 and x is x*(x-5). You then multiply each term on the left hand side by: The equation editor has crapped out at least on my version of Firefox. (x (x - 5))/(x (x - 5)) Multiply the above, which is equal to one, by each term on the right hand side. I have go to break off right now. Google "how to combine fractions algebra"
anonymous
  • anonymous
Sorry. multiply each term on the left hand side. The solutions are x = -5/11 and x = 4 Got to go.

Looking for something else?

Not the answer you are looking for? Search for more explanations.