## anonymous 5 years ago find the area of the region enclosed between the graphs of y=(64x)^(1/4) and y=x

1. anonymous

First you need to find the intersection of those graphs so you know what your limits of integration will be

2. anonymous

64(x)^(1/4)=x, solving for x yields the integration intervals.

3. anonymous

Then integrate ((64)(x^(1/4)) - x) on that interval.

4. anonymous

x = 0, 256

5. anonymous

$\int\limits_{0}^{256}(64x^.25-x)dx$

6. anonymous

19660.8

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