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anonymous
 5 years ago
who can help me with calculus??!!
anonymous
 5 years ago
who can help me with calculus??!!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok it has tpo do with integrals

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits\limits_{1}^{7} 1/\sqrt[3]{t} dt\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if \[f(x)=1/\sqrt[3]{t}\] \[F(x)=(3/2)\sqrt[3]{t}^2\] The result is F(7)  F(1) Calculate that for yourself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{3}^{b} 3x ^{2} dx = 37 \]

Jit4won
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{3}^{b}\]\[\int\limits_{}^{}3x ^{2}dx = 3x^{3}/3 = x^3\]

Jit4won
 5 years ago
Best ResponseYou've already chosen the best response.0substituting the limits we get \[b^3  3 ^3 \]

Jit4won
 5 years ago
Best ResponseYou've already chosen the best response.0now \[b^3  3^3 = 37 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what happen to the 37?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh i get it now thnaks!

Jit4won
 5 years ago
Best ResponseYou've already chosen the best response.0You may email me or skype

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can i ask you another question? i have a final tomorrow lol

Jit4won
 5 years ago
Best ResponseYou've already chosen the best response.0Do u use skype? so that i could instruct you
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