anonymous
  • anonymous
How do you find the range, variance, and standard deviation of a set of data?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
The range of a set is the largest value of the set minus the smallest value of the set. The variance: Make N the mean of the set, the variance is then (X0 + N)^2 + (X1 + N)^2 + ... (Xn + N)^2
anonymous
  • anonymous
so the rage should be one number, correct?
anonymous
  • anonymous
Standard deviation is the square root of the variance.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Suppose we have set of reals S = {0, 2, 75, -2} The range is 75 --2 = 77
dumbcow
  • dumbcow
Range is max value - min value \[Variance = \frac{\sum_{}^{}(X - x_{i})^{2}}{n-1}\]
anonymous
  • anonymous
Thanks! I'm still confused with variance
anonymous
  • anonymous
Suppose we have set of reals S = {0, 2, 75, -2} The mean is S is (0 + 2 + 75 - 2) / 4 = 18.75 The variance is ((0 + 18.75)^2 + (2 + 18.75)^2 + (75 + 18.75)^2 + (18.75 - 2)^2) / (4 - 1)

Looking for something else?

Not the answer you are looking for? Search for more explanations.