anonymous
  • anonymous
if y=Sin[2^x]. To find dy/dx using the chain rule (dy/dx = dy/du du/dx) we have u= what? A. Sin[x] B. 2^x C. (2^x)Ln[2]Cos[2^x]Sin[2^x] D. none of the above.
Mathematics
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anonymous
  • anonymous
if y=Sin[2^x]. To find dy/dx using the chain rule (dy/dx = dy/du du/dx) we have u= what? A. Sin[x] B. 2^x C. (2^x)Ln[2]Cos[2^x]Sin[2^x] D. none of the above.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
you are trying to solve this using substitution and they are asking you what will you use for u?
anonymous
  • anonymous
is it 2^x?
anonymous
  • anonymous
reo.j.syhat: that's correct

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anonymous
  • anonymous
reo is right that will give you sin(u)
anonymous
  • anonymous
ok, on the inside function ur going to use d/dx(a^x) = lna(a^x)
anonymous
  • anonymous
for the outside function, recognize that d/dx(sinx) = cosx
anonymous
  • anonymous
so c would be correct, i think

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