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anonymous

  • 5 years ago

antiderivative of arctan(2x)dx

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  1. anonymous
    • 5 years ago
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    use integration by parts, let u = arctan(2x), let dv = dx

  2. anonymous
    • 5 years ago
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    int(udv) = uv - int(vdu)

  3. anonymous
    • 5 years ago
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    got it?

  4. anonymous
    • 5 years ago
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    yeah..du=1/1+x^2 right

  5. anonymous
    • 5 years ago
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    2/1 + x^2, dont forget the chain rule!

  6. anonymous
    • 5 years ago
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    ooh yeah..got it

  7. anonymous
    • 5 years ago
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    i guess i have to memorize all the trig identiities and derivitaves and antiderivative..it sux my exam is 2moro

  8. anonymous
    • 5 years ago
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    u should get, xarctan(2x) - ln abs(1 _ x^2) + C

  9. anonymous
    • 5 years ago
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    1 + x^2

  10. anonymous
    • 5 years ago
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    my bad

  11. anonymous
    • 5 years ago
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    medal please lol

  12. anonymous
    • 5 years ago
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    Alternative method. Let 2x be theta. Make a right triangle of theta where 2x is opposite, 1 is adjacent. New antiderivative is antiderivative of tan of theta. After antiderivative go back to the triangle to change to original values.

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spraguer (Moderator)
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