antiderivative of arctan(2x)dx

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antiderivative of arctan(2x)dx

Mathematics
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use integration by parts, let u = arctan(2x), let dv = dx
int(udv) = uv - int(vdu)
got it?

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Other answers:

yeah..du=1/1+x^2 right
2/1 + x^2, dont forget the chain rule!
ooh yeah..got it
i guess i have to memorize all the trig identiities and derivitaves and antiderivative..it sux my exam is 2moro
u should get, xarctan(2x) - ln abs(1 _ x^2) + C
1 + x^2
my bad
medal please lol
Alternative method. Let 2x be theta. Make a right triangle of theta where 2x is opposite, 1 is adjacent. New antiderivative is antiderivative of tan of theta. After antiderivative go back to the triangle to change to original values.

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