anonymous
  • anonymous
Assume that sin x =.8 and sin y =(square root(.75)) X and Y lie between 0 and ((pi)/2) Evaluate sin (x+y) Show all work Please?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
sin(x+y)=sin(x)cos(y)+sin(y)cos(x) sin(x)=.8 therefore cos(x)= \[\sqrt{1-.8^{2}}\] = \[\sqrt{1-.64}=\sqrt{.36}=.6\] sin(y)=root(.75) so \[\cos(y)=\sqrt{1-\sqrt{.75}}=\sqrt{1-.75}=\sqrt{.25}=.5\] both sine and cosine are positive because in quadrant 1. hence \[\sin(x+y)=\sin(x)\cos(y) + \cos(x)\sin(y)=.8\times.5+.6\times \sqrt{.75}\]
anonymous
  • anonymous
oops typo. \[\cos(y)=\sqrt{1-\sqrt{.75}^2}=\sqrt{1-.75}=\sqrt{.25}=.5\]
anonymous
  • anonymous
nostalgic?

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anonymous
  • anonymous
wow
anonymous
  • anonymous
the good old days. before drawing before "legend" before wiggling icons
Hero
  • Hero
Ha! Not anymore, lol |dw:1315174785845:dw|

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