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anonymous
 5 years ago
Assume that sin x =.8 and sin y =(square root(.75))
X and Y lie between 0 and ((pi)/2) Evaluate sin (x+y) Show all work Please?
anonymous
 5 years ago
Assume that sin x =.8 and sin y =(square root(.75)) X and Y lie between 0 and ((pi)/2) Evaluate sin (x+y) Show all work Please?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(x+y)=sin(x)cos(y)+sin(y)cos(x) sin(x)=.8 therefore cos(x)= \[\sqrt{1.8^{2}}\] = \[\sqrt{1.64}=\sqrt{.36}=.6\] sin(y)=root(.75) so \[\cos(y)=\sqrt{1\sqrt{.75}}=\sqrt{1.75}=\sqrt{.25}=.5\] both sine and cosine are positive because in quadrant 1. hence \[\sin(x+y)=\sin(x)\cos(y) + \cos(x)\sin(y)=.8\times.5+.6\times \sqrt{.75}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops typo. \[\cos(y)=\sqrt{1\sqrt{.75}^2}=\sqrt{1.75}=\sqrt{.25}=.5\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the good old days. before drawing before "legend" before wiggling icons

Hero
 5 years ago
Best ResponseYou've already chosen the best response.0Ha! Not anymore, lol dw:1315174785845:dw
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