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anonymous
 5 years ago
How does one parametrize the function z^2=sqrt(x^2+y^2)/3?
anonymous
 5 years ago
How does one parametrize the function z^2=sqrt(x^2+y^2)/3?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0BTW its a Conic frustum

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Swing z^2 on the other side and find derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually I typed it wrong its z=sqrt(x^2+y^2)3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ugh z=sqrt(x^2+y^2)/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find derivative, find magnitude of derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The derivative with respect to what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This function need to be a vector, so partial fractions to get <x,y,z>
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