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anonymous
 5 years ago
How do I get the quadratic root equation numbers from a graph?
anonymous
 5 years ago
How do I get the quadratic root equation numbers from a graph?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well what does it mean to have the root of an equation? it means you have the 0s right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know how to balance, but how do I get the ax2+bx+c #s from it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well first thing you want to do is find where it intersects the axis correct? where it intersects is going to give you your roots. so you will have something like (x+5)(x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you can foil that guy out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, the points on the xaxis incept are the roots?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well isnt that how we defined the quadratic equation? the quadratic equation is set up such that your solving for the left hand side to equal 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if i have a graph and the two parabola intercepts are 2 and 2, then are those the roots, or are those the x +2 and x2, or do they fit into the ax2+bx+c?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh you have multiple graphs?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i have one graph, it's a parabola that intercepts the xaxis twice

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats the equation of a parabola? the general syntax? that should help you quite a bit if you analyze what happens with the parabola equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just don't know the equation for turning graph data into the qudratic root formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok well think about (x+2)(x2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that goes to x^2  4 correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your graph intercepts the y axis at 4 im guessing?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well.. you can change where it intercepts the y axis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that "c", where it intercepts?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk the equation for the parabola im justi thinking of how the graph works out intuitevely

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean i have the equation. but think about it like this. (x^2  4)/c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the c is going to effect the 'width' of the graph

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the x and y intercepts are still at 2 and 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0those are both the x intercepts the yone is 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the c is going to change where it intercepts the y axis. you can solve for what c has to be though for the y intercept.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Set x to 0 and y to 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know c=yintercept, right? do i still use ax2... etc etc or do i use y=ax2 + c and how do i get "a"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well in my example my 'a' would be 1/C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and your 'c' would be my 4/C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so y = 1X^24 where a = 1 and C = 4...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0X intercepts are the roots?
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