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well what does it mean to have the root of an equation? it means you have the 0s right?

i know how to balance, but how do I get the ax2+bx+c #s from it?

then you can foil that guy out

oh, the points on the x-axis incept are the roots?

on the x-axis

oh you have multiple graphs?

no i have one graph, it's a parabola that intercepts the x-axis twice

i just don't know the equation for turning graph data into the qudratic root formula

ok
well think about (x+2)(x-2)

that goes to x^2 - 4 correct?

your graph intercepts the y axis at -4 im guessing?

well.. you can change where it intercepts the y axis

is that "c", where it intercepts?

idk the equation for the parabola im justi thinking of how the graph works out intuitevely

i mean i have the equation. but think about it like this. (x^2 - 4)/c

the c is going to effect the 'width' of the graph

the x and y intercepts are still at 2 and -2

those are both the x intercepts the y-one is -4

y = (x^2-4)/C

Set x to 0 and y to -4

solve for C

well in my example my 'a' would be 1/C

and your 'c' would be my 4/C

so y = 1X^2-4 where a = 1 and C = -4...

X intercepts are the roots?