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anonymous

  • 5 years ago

How do I find the domain of f(x) = (-x^2+16/x^2-2x-3)

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  1. anonymous
    • 5 years ago
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    whenever you have a fraction function, the domain will be: (bottom part) > 0

  2. anonymous
    • 5 years ago
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    false; it is all x values that will make the bottom not equal to 0.

  3. anonymous
    • 5 years ago
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    so, \[x^{2} - 2x - 3 \neq 0 \] solve for x and it'll give yu yur domain

  4. anonymous
    • 5 years ago
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    set the denominator = 0 solve. x^2-2x-3=0 (x+1)(x-3)=0 x=-1 or x = 3 domain is all real numbers except -1 and 3

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