anonymous
  • anonymous
The temperature outside dropped from 42 degrees at 5:00 am to 24 degrees at 5:00 pm. Find the rate of change in the temperature
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
do you have the general formula?
anonymous
  • anonymous
No I do not
anonymous
  • anonymous
use:( y" -y')?(x"-x1)

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anonymous
  • anonymous
The temperature dropped 18 degrees (42-24) in 12 hours, so the rate of change was a decrease of 1.5 degrees per hour. (18/12) or Newton's Law of Cooling? T(t) = Ts + (To - Ts)*e^(-k*t) ; where: t is the time in the preferred units (seconds, minutes, hours, etc.) T(t) is the temperature of the object at time t Ts is the sorrounding constant temperature To is the initial temperature of the object k is a constant to be found
anonymous
  • anonymous
Is the y2= 42 or 24? Is the y1 = 42 or 24?
anonymous
  • anonymous
y2=5pm,y1=5am subtrac you get 12 x2=24, x1= 42 subtrac you det negative =-18 slope= 12/-18=-3/4 the rate -3/4
anonymous
  • anonymous
sorry -3/2 not -3/4

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