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anonymous
 5 years ago
assume that a perfessional baseball team has 11 ptchers,5 infielders, and 10 other players. if 3 players names are selected at random, determine the probl that all 3 are infielders.
anonymous
 5 years ago
assume that a perfessional baseball team has 11 ptchers,5 infielders, and 10 other players. if 3 players names are selected at random, determine the probl that all 3 are infielders.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05 choose 3 divided by 21 choose 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Satellite already gave you the answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats does 5 choose 3 devided by 21 choose 3 mean its only suppose to be 1 number rite

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Choose is the name we sometimes give to the binomial coefficient function: \[\text{n choose k} = {n\choose k} = \frac{n!}{k!(nk)!}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05 choose 3 = \(\frac{5!}{3!(53)!}\) 21 choose 3 = \(\frac{21!}{3!(213)!}\) Then divide those two values to find \[\frac{\text{5 choose 3}}{\text{21 choose 3}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because when u do 21/3 it equals 7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you being taught to do this on your calculator using the Cr function?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no we don't use our calculators for it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Doing it by hand you have \[\frac{21!}{3!*18!} = \frac{21*20*19*18!}{3! * 18!} = \frac{21*20*19}{3*2} \]\[= 7*10*19 = 70*19 = 700 + 630= 1330\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But that will make for a very long evening.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can i butt in for a moment?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If i want to know the number of ways to choose 3 people (items, whatever) out of a set of 21 I reason as follows: there are 21 choices for the first person, 20 for the next and then 19 for the last. by the counting principle there are then 21*20*19 ways to do this. But this counts (a,b,c) differently than (b,c,a) for example so I have overcounted by the number of ways I can permute 3 things. There are 3*2 = 6 such permutations. Thus the number of ways to choose 3 from a set of 21 is 21*20*19/3*2. Similarly the number of ways to choose 3 from a set of 5 is 5*4*3/3*2 and the number of ways to choose 4 out of 11 is 11*10*9*8/4*3*2 etc

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hello, Your chance of picking one is 5/26, then, once you've picked him, there are only 4 left out of 25 and once you've picked that player, there's only 3 left out of 24 to choose from (like in elementary school picking teams) giving you: (5/26)*(4/25)*(3/24) = 1/260, like you said.
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