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anonymous

  • 5 years ago

7 men and 8 woman are going to be assigned seats in a movie theather. if 15 tickets with numbered seats are given at ramdom, find the prob that exaclty one man is in one of the first 5 seats

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  1. anonymous
    • 5 years ago
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    35*210? Here's my reasoning: there are five ways any man can sit in the first five seats: MWWWW WMWWW WWMWW WWWMW WWWWM And there are seven men that can be that man, so 5*7 = 35 Now , the remaining ten seats have 6 men left to seat, which has this many arrangements: (10*9*8*7*6*5)/(6!) = 210 35 * 210 = 7350

  2. anonymous
    • 5 years ago
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    wronggg

  3. anonymous
    • 5 years ago
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    its suppose to be a fraction

  4. anonymous
    • 5 years ago
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    Oooooh, ok

  5. anonymous
    • 5 years ago
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    then it is 7350 out of 259459200

  6. anonymous
    • 5 years ago
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    so 7350/259459200

  7. anonymous
    • 5 years ago
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    well, it reduces

  8. anonymous
    • 5 years ago
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    147/5189184, which seems ridiculous

  9. anonymous
    • 5 years ago
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    is it right

  10. anonymous
    • 5 years ago
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    hold on...

  11. anonymous
    • 5 years ago
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    The total number of choices for people to sit is...

  12. anonymous
    • 5 years ago
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    is

  13. anonymous
    • 5 years ago
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    I don;t know why I can't get the total. I'll brb

  14. anonymous
    • 5 years ago
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    kk

  15. anonymous
    • 5 years ago
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    okay, try this, it doesn't matter which man it is. that was my mistake, so there aren't 7350 ways they can sit with one man in the first 5 seats, there are only 10C6*5 = 1050. then there are 15C7 total ways, for 6435 total 1050/6435 = 70/429, less ridiculous.

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