anonymous
  • anonymous
7 men and 8 woman are going to be assigned seats in a movie theather. if 15 tickets with numbered seats are given at ramdom, find the prob that exaclty one man is in one of the first 5 seats
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
35*210? Here's my reasoning: there are five ways any man can sit in the first five seats: MWWWW WMWWW WWMWW WWWMW WWWWM And there are seven men that can be that man, so 5*7 = 35 Now , the remaining ten seats have 6 men left to seat, which has this many arrangements: (10*9*8*7*6*5)/(6!) = 210 35 * 210 = 7350
anonymous
  • anonymous
wronggg
anonymous
  • anonymous
its suppose to be a fraction

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anonymous
  • anonymous
Oooooh, ok
anonymous
  • anonymous
then it is 7350 out of 259459200
anonymous
  • anonymous
so 7350/259459200
anonymous
  • anonymous
well, it reduces
anonymous
  • anonymous
147/5189184, which seems ridiculous
anonymous
  • anonymous
is it right
anonymous
  • anonymous
hold on...
anonymous
  • anonymous
The total number of choices for people to sit is...
anonymous
  • anonymous
is
anonymous
  • anonymous
I don;t know why I can't get the total. I'll brb
anonymous
  • anonymous
kk
anonymous
  • anonymous
okay, try this, it doesn't matter which man it is. that was my mistake, so there aren't 7350 ways they can sit with one man in the first 5 seats, there are only 10C6*5 = 1050. then there are 15C7 total ways, for 6435 total 1050/6435 = 70/429, less ridiculous.

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