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anonymous
 5 years ago
7 men and 8 woman are going to be assigned seats in a movie theather. if 15 tickets with numbered seats are given at ramdom, find the prob that exaclty one man is in one of the first 5 seats
anonymous
 5 years ago
7 men and 8 woman are going to be assigned seats in a movie theather. if 15 tickets with numbered seats are given at ramdom, find the prob that exaclty one man is in one of the first 5 seats

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.035*210? Here's my reasoning: there are five ways any man can sit in the first five seats: MWWWW WMWWW WWMWW WWWMW WWWWM And there are seven men that can be that man, so 5*7 = 35 Now , the remaining ten seats have 6 men left to seat, which has this many arrangements: (10*9*8*7*6*5)/(6!) = 210 35 * 210 = 7350

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its suppose to be a fraction

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then it is 7350 out of 259459200

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0147/5189184, which seems ridiculous

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The total number of choices for people to sit is...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don;t know why I can't get the total. I'll brb

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, try this, it doesn't matter which man it is. that was my mistake, so there aren't 7350 ways they can sit with one man in the first 5 seats, there are only 10C6*5 = 1050. then there are 15C7 total ways, for 6435 total 1050/6435 = 70/429, less ridiculous.
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