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anonymous
 5 years ago
(3sqrt(7) 6sqrt(3)) (3sqrt(7) +9sqrt(3)) multiply to solve.
anonymous
 5 years ago
(3sqrt(7) 6sqrt(3)) (3sqrt(7) +9sqrt(3)) multiply to solve.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01.) 3sqrt(2) * [3 + sqrt(2)] Distribute for each term: 9sqrt(2) + 3sqrt(2)*sqrt(2) (Multiplying like roots cancels it out to the actual number, 2 in this case) 9sqrt(2) + 3*2 9sqrt(2) + 6 2.) 4 + sqrt(20)/2 Assuming that the 2 is being divided into ONLY the sqrt(20)... 4 + 2sqrt(5)/2 (The 2s cancel here because of division) 4 + sqrt(5) In the case that the 2 is being divided into BOTH the 4 and the sqrt(2)... [4 + 2sqrt(5)]/2 2 + sqrt(5) 3.) 12sqrt(18)/3sqrt(2) Again, simplify the roots as much as possible... 12*3sqrt(2)/3sqrt(2) (The 3sqrt(2) cancels because of division) 12 So, your answers are 1.) 9sqrt(2) + 6 2.) 4 + sqrt(5) (or 2 + sqrt(5), depending) 3.) 12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow, great explanation!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(3\sqrt{7} 6\sqrt3) (3\sqrt7 +9\sqrt3) = 9*7 + 27\sqrt21  18\sqrt21  54*3 = 63 + 9\sqrt21  162 = 99 + 9\sqrt21\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the answer is 63+9sqrt(2116)
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