anonymous
  • anonymous
11 pictchers, 7 infielders, and 12 other players. if 3 players are selected at ramdom, determine the probl that all 3 are infliders
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
OK so we start off the same way!
anonymous
  • anonymous
Yes, you can do this, it is just like the other two...
anonymous
  • anonymous
7/30?

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More answers

anonymous
  • anonymous
for the first selection, yes, now what for the second? (remember that one infielder is removed by you choosing him.
anonymous
  • anonymous
6/29
anonymous
  • anonymous
right, then the third selection...
anonymous
  • anonymous
5/28
anonymous
  • anonymous
okay, now multiply...
anonymous
  • anonymous
so u do 30 times 29 times 28?
anonymous
  • anonymous
cancel first... it's easier
anonymous
  • anonymous
then 6 times 5 times 4?
anonymous
  • anonymous
I mean 7,6 and 5?
anonymous
  • anonymous
(7*6*5)/(30*29*28) ...the 6*5 cancels with the 30, making it easier
anonymous
  • anonymous
...=7/(29*28)
anonymous
  • anonymous
oh, wait keep canceling...
anonymous
  • anonymous
7/28 = 1/4 so 7/(28*29) = 1/(4*29)
anonymous
  • anonymous
what?
anonymous
  • anonymous
7 times 6 times 5 is 210
anonymous
  • anonymous
yes, but it is easier to cancel before you multiply than to multiply then reduce
anonymous
  • anonymous
so what would it be when u cancel 210/2?
anonymous
  • anonymous
do you want to wrangle with reducing 210/24360?
anonymous
  • anonymous
210/24360 = 1/116
anonymous
  • anonymous
116?
anonymous
  • anonymous
Great job on figuring out the probability part, we only got hung up on the arithmetic. When is the quiz?
anonymous
  • anonymous
Well I am doing h/w now and then next week he usually gives us the quiz like after monday
anonymous
  • anonymous
then we have a week to work on it

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