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anonymous
 5 years ago
11 pictchers, 7 infielders, and 12 other players. if 3 players are selected at ramdom, determine the probl that all 3 are infliders
anonymous
 5 years ago
11 pictchers, 7 infielders, and 12 other players. if 3 players are selected at ramdom, determine the probl that all 3 are infliders

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK so we start off the same way!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, you can do this, it is just like the other two...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the first selection, yes, now what for the second? (remember that one infielder is removed by you choosing him.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right, then the third selection...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, now multiply...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so u do 30 times 29 times 28?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cancel first... it's easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then 6 times 5 times 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(7*6*5)/(30*29*28) ...the 6*5 cancels with the 30, making it easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, wait keep canceling...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07/28 = 1/4 so 7/(28*29) = 1/(4*29)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07 times 6 times 5 is 210

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, but it is easier to cancel before you multiply than to multiply then reduce

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what would it be when u cancel 210/2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you want to wrangle with reducing 210/24360?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great job on figuring out the probability part, we only got hung up on the arithmetic. When is the quiz?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well I am doing h/w now and then next week he usually gives us the quiz like after monday

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then we have a week to work on it
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